extract values with java regex

Question

I begin with regex and i want extract values from a String like this

String test="[ABC]Name:User:Date: Adresse ";

I want extract Name, User , Date and Adresse I can do the trick with substring and split

String test = "String test="[ABC]Name:User:Date: Adresse ";
        String test2= test.substring(5,test.length());
        System.out.println(test2);
        String[] chaine = test2.split(":");
        for(String s :chaine)
        {
            System.out.println("Valeur " + s);
        }

but i want try with regex , i did

pattern = Pattern.compile("^[(ABC)|:].");

but it doesn ' t work

Can you help me please ?

Thanks a lot

João Silva · Accepted Answer · 2011-08-04 15:30:46Z

1

String#split is really the best way to accomplish what you are trying to do. Having said that, with regex, the following will give you the same output:

    Pattern p = Pattern.compile("^(?:\\[ABC\\])([^:]+):([^:]+):([^:]+):([^:]+)$");
    Matcher m = p.matcher(test);
    while (m.find()) {
        System.out.println("Valeur " + m.group(1)); // Name
        System.out.println("Valeur " + m.group(2)); // User
        System.out.println("Valeur " + m.group(3)); // Date
        System.out.println("Valeur " + m.group(4)); // Address
    }

edited Aug 4, 2011 at 15:30

answered Aug 4, 2011 at 15:05

João Silva

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6 Comments

user799698 Over a year ago

Ok thanks for your help , but if i want to negate [ABC] in order to get only Name how can i do that ?

João Silva Over a year ago

Not sure what you are asking for, but I've updated the code so that each group will map to a single element in the original string. Basically, when you wrap an expression with (), you capture that group, and you can fetch it later with Matcher.

user799698 Over a year ago

Thanks a lot! It work perfectly but the regex became more complicated :p. I need practices so i will read some tutorials about regex . btw thanks you again !

toto2 Over a year ago

You'll capture the empty spaces too. There are some spaces around the address in the example, which I guess you would like to eliminate. You could fix it with :\s*([^:]+)\s*$. It still keeps the spaces inside the address. Also, I'm a bit fuzzy about the example: is it really starting with [ABC] or does it include all the rest. If it's the latter it gets complicated with the start ^ and end $.

user799698 Over a year ago

Ok , thanks toto, i will update the code with your advices . Yeah , my String begin with[ABC] , here is an exemple [ABC]STRUTS:PAUL:25/06/2011T10H12:8 Rue Pierre de Coubertin 95300 Pontoise" . I must just extract the values between ":" without [ABC]

|

user177800 · Accepted Answer · 2011-08-04 15:04:38Z

0

You have to escape the [ and ] here is a working example.

^\[(.*)\](.*):(.*):(.*):(.*)$

Note that your code is probably more easily maintained than regular expressions in cases where the regular expression becomes complex.

Some people, when confronted with a problem, think "I know, I'll use regular expressions." Now they have two problems. - Jamie Zawinski

answered Aug 4, 2011 at 15:04

user177800

1 Comment

user799698 Over a year ago

Thanks for the advice and your citation is really correct but i want juste learn a little regex in order to practice

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