Make an argument when calling php.exe in a batch file

Question

I want to start c:...\php.exe and add the argment c:...\upload.php"

into my batch file but anytime I do it it says wrong Paramter.

I even tried setting an argument by saying:

@echo off
set arg1=%1


start ""c:\...\php.exe" %1"c:\...\upload.php"%1"

still wont work, thanks in advance guys.

Jonathan Kuhn · Accepted Answer · 2011-08-04 15:22:21Z

2

There is a whole section of the manual dedicated to command line usage. Usually though, you would just specify several arguments as space separated after the script name and you can access them in your script with $argv. Example:

<?php print_r($argv); ?>

then run with

php.exe test.php test1 test2

answered Aug 4, 2011 at 15:22

Jonathan Kuhn

15.3k3 gold badges34 silver badges43 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Marc B · Accepted Answer · 2011-08-04 15:18:50Z

1

You've got mis-matched quotes. They're only necessary if the window title and/or command path have spaces in them. Try

start "" "c:\...\php.exe" "c:\...\upload.php"
      ^^---window title
         ^^^^^^^^^^^^^^^^--- command
                          ^^^^^^^^^^^^^^^^ argument

answered Aug 4, 2011 at 15:18

Marc B

362k44 gold badges433 silver badges508 bronze badges

Collectives™ on Stack Overflow

Make an argument when calling php.exe in a batch file

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related