how to add formatting to output statement in C

Question

My code works fully but for full credit we need to include a comma after every number except the last one. I'm not sure where I should place it seeing as where ever it ends up either in the for loop or out, it does not produce the correct look.

My code produces 25 0 33 like it should be needs to look like 25, 0, 33

Sample inputs: 5 25 51 0 200 33 0 50

    #include <stdio.h>

int main() {
   
   int numVals;
   int max, min;
   
   printf("How many integers to enter?\n");
   scanf("%d", &numVals);
   
   int array[numVals];
   
   printf("Please enter %d integers: \n", numVals);
   
   for (int i = 0; i < numVals; ++i) {
      scanf("%d", &array[i]);
   }
   
   printf("Lower and upper bounds: \n");
   scanf("%d %d", max, min);
   
   for (i = 0; i < numVals; ++i) {
      if (array[i] >= min && arr[i] <= max {
         printf("%d", array[i]);
      }
   }
   
   return 0;
}

In your loop, can you determine if you're on the last iteration? If you can, then only print a trailing "., " if that's not true. — Chris
– Chris, Commented Oct 6, 2021 at 2:03
It's easier to determine whether you're on the first iteration, and then only print a leading comma if that's not true. — Steve Summit
– Steve Summit, Commented Oct 6, 2021 at 2:05
Your other alternative is printf (i>0?", %d":"%d", array[i]); By setting the i>0 condition, branch prediction will minimize the impact of the conditional only taking the false path of the ternary on the first iteration. — David C. Rankin
– David C. Rankin, Commented Oct 6, 2021 at 3:24

chux · Accepted Answer · 2021-10-06 02:31:14Z

6

A simple way is to change the separator after the first number.

 const char *sep = "";
 for (i = 0; i < numVals; ++i) {
    if (array[i] >= min && arr[i] <= max) {
       printf("%s%d", sep, array[i]);
       sep = ", ";
    }
 }
 prinf("\n");

edited Oct 6, 2021 at 2:31

answered Oct 6, 2021 at 2:11

chux

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