Sort an array of objects, using a specific key's value

Question

I currently have a set of data that contains an array of objects which have 12 indexs, and 2 values each.

Each one of the index contains the keys 'months' and 'year'. Months is a sub-array, and year is a string value (could easily be made a int).

I'm looking to sort my array of objects by the value of the year key

. For instance, currently, my data looks like this

0: {months: {…}, year: "2017"}
1: {months: {…}, year: "2019"}
2: {months: {…}, year: "2018"}
3: {months: {…}, year: "2011"}
4: {months: {…}, year: "2010"}
5: {months: {…}, year: "2012"}
6: {months: {…}, year: "2013"}
7: {months: {…}, year: "2015"}
8: {months: {…}, year: "2014"}
9: {months: {…}, year: "2016"}

I'm trying to sort this from years lowest -> highest. I tried using map, but I couldn't figure out the correct function. Any advice would be great, thank you.

Sajeeb Ahamed · Accepted Answer · 2021-10-10 16:09:09Z

2

This is pretty simple. Sort the array using the Array.prototype.sort function. As the year is a string value so you have to parse it as an integer for sorting. Try this-

const data = [
  { months: null, year: "2017" },
  { months: null, year: "2019" },
  { months: null, year: "2018" },
  { months: null, year: "2011" },
  { months: null, year: "2010" },
  { months: null, year: "2012" },
  { months: null, year: "2013" },
  { months: null, year: "2015" },
  { months: null, year: "2014" },
  { months: null, year: "2016" },
];

data.sort((a, b) => parseInt(a.year) - parseInt(b.year));
console.log(data);

answered Oct 10, 2021 at 16:09

Sajeeb Ahamed

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sonEtLumiere · Accepted Answer · 2021-10-10 16:10:08Z

0

Try this:

let data = [
  {months: {a: 'a'}, year: "2017"},
  {months: {a: 'a'}, year: "2019"},
  {months: {a: 'a'}, year: "2018"},
  {months: {a: 'a'}, year: "2011"},
  {months: {a: 'a'}, year: "2010"},
  {months: {a: 'a'}, year: "2012"},
  {months: {a: 'a'}, year: "2013"},
  {months: {a: 'a'}, year: "2015"},
  {months: {a: 'a'}, year: "2014"},
  {months: {a: 'a'}, year: "2016"}
];

let sorted = data.sort((a, b) => a.year - b.year);
console.log(sorted);

answered Oct 10, 2021 at 16:10

sonEtLumiere

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Comments

navnath · Accepted Answer · 2021-10-10 16:16:18Z

0

Using Array.sort pass compare function to it.

const arr = [{months:[],year:"2017"},{months:[],year:"2019"},{months:[],year:"2018"},{months:[],year:"2011"},{months:[],year:"2010"},{months:[],year:"2012"},{months:[],year:"2016"},];

const res = arr.sort((a, b) => a.year - b.year);

console.log(res);

edited Oct 10, 2021 at 16:16

answered Oct 10, 2021 at 16:10

navnath

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