Finding if List in Input()

Question

I'm attempting to find out when a list is in someone's input, here's the code:

Sad = ['sad','broken','depressed','sadness','grief',]

Input = input("Hi ").strip()

if Sad in Input:
    print("Word Found")
else:
    print("Word Not Found")

It works when you have one of the words in the list alone, but when it's a sentence including the word it returns as false.

Agate · Accepted Answer · 2021-10-10 23:24:42Z

2

You're close, it's the reverse: if Input in Sad: you're trying to find an element, Input, in the Sad list ;)

If you want it to work with sentences in Input, you'll have to update your logic:

Split Input into a list of word
Loop on each word
See if the word is present in Sad

Sad = ['sad','broken','depressed','sadness','grief',]


# split(" ") will split the string that is given as an input
# into a list of strings, using " " as a separator.
Input = input("Hi ").strip().split(" ")

for word in in Input:
    if word in Sad:
        print("Word {} Found".format(word)
    else:
        print("Word {} Not Found".format(word)

You can make this even easier using sets:


Sad = {'sad','broken','depressed','sadness','grief'}
Input = set(input("Hi ").strip().split(" "))
matching_words = Input & Sad

if matching_words:
    print("Some words found:", matching_words)
else:
    print("No words found)

edited Oct 10, 2021 at 23:24

answered Oct 10, 2021 at 22:50

Agate

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12 Comments

Kreighstan Over a year ago

This works, but ran into the other issue. It returns false if you add another word onto it. (Responding to Agate unsure of whether the @ went through).

Agate Over a year ago

if you add another word onto it -> do you mean in the Input ?

Kreighstan Over a year ago

Yes, when I put, "Sad", for the input it clarifies at as true but if I put, "I am sad", it clarifies it as false.

Kreighstan Over a year ago

Ignore my last response, I have a literal coconut for a brain and didnt realize it prints not word for every word that isn't in the list.

Jab Over a year ago

I would suggest changing Sad to a set for more efficient membership checks.

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