Pass function name as argument when running bash script

Question

Assuming I have the following script:

#!/bin/bash

function hello (){
    echo hello,
}

function world (){
    echo world!
}

Is it possible to select the functions to run while I start the script? For exmaple:

./test.sh hello world

output:

hello,world!

KamilCuk · Accepted Answer · 2021-10-13 17:58:41Z

5

Just iterate over the arguments and run them.

for i in "$@"; do
    "$i"
done

Do not use function name(), just name(). See https://wiki.bash-hackers.org/scripting/obsolete . Check your scripts with shellcheck .

answered Oct 13, 2021 at 17:58

KamilCuk

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2 Comments

That about covers it all -- you left nothing to add...

Thank you very much.

Saboteur · Accepted Answer · 2021-10-13 20:45:30Z

-1

You can use eval command to execute first argument.

#!/bin/bash

function hello (){
    echo hello,
}

function world (){
    echo world!
}

eval $1

answered Oct 13, 2021 at 20:45

Saboteur

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