Function to Generate Random Coordinate Points Python

Question

I am trying to create a function which will give me 70 random coordinate points. This is the code I have now:

# Generate test data
points = []
for _ in range(70):
    x = random()
    y = random()
    points.append((x, y))
    print(points)

but the code I have creates an output such as: [(0.4107139467174139, 0.3864211980981259)] [(0.4107139467174139, 0.3864211980981259), (0.6159949847158482, 0.6526570064673685)] [(0.4107139467174139, 0.3864211980981259), (0.6159949847158482, 0.6526570064673685), (0.6515694521853568, 0.9651948000023821)] ...

I have also tried:

# Generate test data
cord_set = []
for _ in range(70):
    x = random()
    y = random()
    cord_set.append((x, y))
    print(cord_set)

With similar results.

Ok, what don't you like about what it's generating? What's your expected range? And which random() are you even calling? The title of your question isn't even a question - try rephrasing it to state what specifically is wrong. See How to Ask — msanford
– msanford, Commented Oct 16, 2021 at 2:16
@msanford I want an output such as (x1, y1), (x2, y2), etc. It doesn't have to be within a specific range. — Learning and Improving
– Learning and Improving, Commented Oct 16, 2021 at 2:19

Zichzheng · Accepted Answer · 2021-10-16 02:57:41Z

1

In the comment section, you mentioned that you just want an output like (x1, y1), (x2, y2), the reason why you are getting this many of list is because in the loop, you print the list points in every iteration. Just remove the print statement out of the loop should give you the output you want.

points = []
for _ in range(70):
    x = random()
    y = random()
    points.append((x, y))
print(points)

Based on your comment, I think you are saying for every iteration, you want the result to be [(x,y)] which is a list. If so, you need to have a temp list to pass those generated value:

points = []
for _ in range(70):
    single_point = []
    x = random()
    y = random()
    single_point.append((x, y))
    points.append(single_point)
print(points)

This gives you [[(x1,y1)],[(x2,y2)],...]

If that is the case, I don't think you will need the () to make it nested. You can just go with:

points = []
for _ in range(70):
    single_point = []
    x = random()
    y = random()
    single_point.append(x)
    single_point.append(y)
    points.append(single_point)
print(points)

This gives you [[x1,y1],[x2,y2]...]

edited Oct 16, 2021 at 2:57

answered Oct 16, 2021 at 2:24

Zichzheng

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2 Comments

Rashid 'Lee' Ibrahim Over a year ago

Just wait till he figures out he's getting the same 2 points over and over...

Learning and Improving Over a year ago

@Zichezeng Unfortunately I need the output to look like: [(x1, y1)] [(x2, y2][(x3, y3)] ... instead of [(x1, y1)] [(x2, y2), (x3, y3)] [(x4, y4), (x5, y5), (x6, x6)]

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