nested json object from a single model

You should declare one more model for PropertyStats. Otherwise, it will be kind of reverse engineering to modify the already created JSON string.

Like this:

public class ApiRequest
{
    [JsonProperty(PropertyName = "name")]
    public string Name { get; set; }
    [JsonProperty(PropertyName = "description")]
    public string Description { get; set; }
    [JsonProperty(PropertyName = "privacy")]
    public PropertyStats PrivacyStats { get; set; }
}

public class PropertyStats
{
    [JsonProperty(PropertyName = "view")]
    public string View { get; set; }
}

Then You can serialize it like this.

static void Main(string[] args)
{
    ApiRequest objApiRequest = new ApiRequest()
    {
        Name = "Test1",
        Description = "Testing Only",
        PrivacyStats = new PropertyStats
        {
            View = "unlisted"
        }
    };

    var serializedString = JsonConvert.SerializeObject(objApiRequest, Formatting.Indented);

    Console.WriteLine(serializedString);
    Console.ReadLine();
}

Output:

{
  "name": "Test1",
  "description": "Testing Only",
  "privacy": {
    "view": "unlisted"
  }
}

In the future, if you want to add additional property to the privacy model then it will be easy to serialize it.

Like below:

public class PropertyStats
{
    [JsonProperty(PropertyName = "view")]
    public string View { get; set; }
    [JsonProperty(PropertyName = "status")]
    public int StatusCode { get; set; }
}

Serialize like it below:

static void Main(string[] args)
{
    ApiRequest objApiRequest = new ApiRequest()
    {
        Name = "Test1",
        Description = "Testing Only",
        PrivacyStats = new PropertyStats
        {
            View = "unlisted",
            StatusCode = 1
        }
    };

    var serializedString = JsonConvert.SerializeObject(objApiRequest, Formatting.Indented);

    Console.WriteLine(serializedString);
    Console.ReadLine();
}

Output:

{
  "name": "Test1",
  "description": "Testing Only",
  "privacy": {
    "view": "unlisted",
    "status": 1
  }
}