how do i extract numbers from each word in a string in python

Question

This is my string

data = 'hs122 125 &55,58, 25'

Expected Result: [122, 125, 55, 58, 25]

Try1:

data = 'hs122 125 &55,58, 25'
s = re.search(r"\d+(\.\d+)?", data)
print(s.group(0))

Output: 122

Try2:

data = 'hs122 125 &55,58, 25'
s = [int(s) for s in data.split() if s.isdigit()]
print(s)

Output: [125, 25]

Try3:

p = '[\d]+[.,\d]+|[\d]*[.][\d]+|[\d]+'
data = 'hs122 125 &55,58, 25'
numbers = []
if re.search(p, data) is not None:
    for catch in re.finditer(p, data):
        numbers.append(catch[0])
print(numbers)

Output: ['122', '125', '55,58,', '25']

Dev · Accepted Answer · 2021-10-21 09:23:28Z

2

try this

import re
data = 'hs122 125 &55,58, 25'

results = list(map(int, re.findall(r'\d+', data)))
print(results)

answered Oct 21, 2021 at 9:23

Dev

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Comments

Maroun · Accepted Answer · 2021-10-21 09:19:40Z

1

You can simply use \d+ with findall:

re.findall(r'\d+', 'hs122 125 &55,58, 25')
# ['122', '125', '55', '58', '25']

answered Oct 21, 2021 at 9:19

Maroun

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