C# using Process in Linux. Problem with passing arguments

Question

My program should start a Linux program and pass arguments to it. For debugging I print FileName and Arguments to the console.

private static void StartRecording(string channelName)
    {
        Console.WriteLine($"Starting recording of the channel {channelName}");
        if (RecordingProcesses.ContainsKey(channelName)) return;
        Process recordingProcess = new Process
        {
            StartInfo = new ProcessStartInfo
            {
                UseShellExecute = false, 
                FileName = RecorderPath,
                Arguments = $"--appId {AppId} --channel {channelName} --uid {RecordingUid} --channelProfile 0 " +
                            $"--appliteDir {AppliteDir} --channelKey {GetToken(channelName)}",
            }
        };
        recordingProcess.Exited += delegate { OnProcessExited(channelName); };
        Console.WriteLine($"Starting process. FileName = {recordingProcess.StartInfo.FileName}, Arguments = {recordingProcess.StartInfo.Arguments}");
        recordingProcess.Start();
        RecordingProcesses.Add(channelName, recordingProcess);
    }

That programs raises an error and says that I use wrong arguments. After that I close the program and try to launch that process manualy through the terminal by copy-pasting the FileName and then Arguments from the debug message to the terminal and the program runs ok. Why does that happen? How can I start the process from my program with the same result as when I start it from the terminal?

perhaps this could be useful to you stackoverflow.com/questions/63237496/… — Aaron Parrilla
– Aaron Parrilla, Commented Oct 21, 2021 at 9:59

Avangardum · Accepted Answer · 2021-10-21 12:25:24Z

3

I found the reason. It was because one of the argments contained a tilde. When running the program from terminal it was replaced by "/root". And when I used Process, it didn't replace tilde.

answered Oct 21, 2021 at 12:25

Avangardum

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1 Comment

b2f Over a year ago

The tilde in terminal is expanded to the user's home. ~ in terminal is the same as $HOME. When the process is not run by your user or the ~ is not expanded, it won't work. I am glad to see you were able to help yourself.

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