Django: How to convert string and int into variable

Question

I have declared a variable as"

a1 = 10

Now in a function I need to call this variable by adding "a"+"1". However result is a1 in string and not above declared variable.

Here is the code:

a1 = 10
b = "a"+"1"
print(b)
a1

when I print b, answer is a1, instead of 10. How can I change this concatenate to declared variable?

Please explain your use case, there may be some better ways to achieve what you are trying to do — JPG
– JPG, Commented Oct 24, 2021 at 12:36
I have 5 different variable and need to update these in a table. Need to loop queryset to update this 5 variables by increasing a1,a2 like this. — Pulkit Sharma
– Pulkit Sharma, Commented Oct 24, 2021 at 12:39
Sorry, I don't quite understand your requirement. Why don't you edit your OP and explain things in a bit more detail? Someone might have a solution for you. — JPG
– JPG, Commented Oct 24, 2021 at 12:41
Looking at my code it seems valid question. Is there any option to arrive at variable by concatenating str and int? Or its not possible? — Pulkit Sharma
– Pulkit Sharma, Commented Oct 24, 2021 at 12:43
Storing your variables in a list or dict instead may be simpler — Iain Shelvington
– Iain Shelvington, Commented Oct 24, 2021 at 12:46

Shreeyansh Jain · Accepted Answer · 2021-10-24 15:43:38Z

1

You can use python inbuilt function eval for such requirements like below :-

>> a1 = 10
>> b = "a"+"1"
>> print(eval(b))
>> 10

answered Oct 24, 2021 at 15:43

Shreeyansh Jain

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1 Comment

Pulkit Sharma Over a year ago

This is the correct answer. Thanks a lot. Wonderfully same eval() works in Javascript.

Rvector · Accepted Answer · 2021-10-24 12:50:36Z

1

if I understand, you want to dynamically create the name of a variable and access it : you can use dict for that i think

a1, a2, a3 = 10, 11, 12
var_dict = {'a1': a1, 'a2': a2, 'a3': a3}

for i in [1, 2, 3]:
    print(var_dict[f"a{i}"])  # f"a{i}" => 'a1', 'a2', 'a3' according to i value

answered Oct 24, 2021 at 12:50

Rvector

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1 Comment

Pulkit Sharma Over a year ago

This is workaround. Correct answer is stackoverflow.com/a/69698328/6303199

Ruggero · Accepted Answer · 2021-10-24 12:44:58Z

0

The statement b = 'a'+'1' means that your new variable b is a string:

>>> b = ['a1']

If you are interested in printing a1, you have just to do:

print(a1)

Making a sum of the letters of a declared variable does not result in the variable itself.

answered Oct 24, 2021 at 12:44

Ruggero

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2 Comments

Pulkit Sharma Over a year ago

There is no way to arrive at variable? cant we convert it to variable?

Ruggero Over a year ago

@PulkitSharma you could make a list of those variables and loop it inside your function

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