Dynamically change the variable at each iteration in a for loop?

Question

Given an arbitrary number of people:

def __init__(self):
    self.person1 = ["Person_1", 0]
    self.person2 = ["Person_2", 0]
    ...

I would like to adjust the value "0" to "25".

How can I change the variable during each iteration so that I don't have to type it as follows:

 def daily_income(self):
    self.person1[1] += 25
    self.person2[1] += 25
    ...

I tried to adjust the variable name by appending the "i" to the end of the variable name, however, it did not work.

def daily_income(self):
    for i in range(1,3):
        'self.person_{}'.format(i)[1] += 25

appending the "i" to the end of the variable name You appended "i" to a string. — Ch3steR
– Ch3steR, Commented Oct 30, 2021 at 13:41
Why not use a single dictionary instead of multiple variables ? — Alain T.
– Alain T., Commented Oct 30, 2021 at 18:36
If you just had one big self.people structure this problem wouldn't exist. — Charles Duffy
– Charles Duffy, Commented Oct 31, 2021 at 4:01

bb1 · Accepted Answer · 2021-10-31 03:36:41Z

1

This is not a good code design, but it can be done as follows:

class People:
    def __init__(self):
        self.person1 = ["Person_1", 1]
        self.person2 = ["Person_1", 2]
        self.person3 = ["Person_1", 3]
        
    def daily_income(self):
        for i in range(1,4):
            attr = 'person{}'.format(i)
            val = getattr(self, attr)
            val[1] += 25
            setattr(self, attr, val)

answered Oct 31, 2021 at 3:36

bb1

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Comments

Joyanta J. Mondal · Accepted Answer · 2021-10-31 04:50:11Z

0

To get the variable, either follow this:

def daily_income(self):
    for i in range(1,26):
        attr = f'person{i}'

or this: (as followed by bb1)

def daily_income(self):
    for i in range(1,26):
        attr = 'person{}'.format(i)
        val = getattr(self, attr)
        val[1] += 25
        setattr(self, attr, val)

answered Oct 31, 2021 at 4:50

Joyanta J. Mondal

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