Consider following array in Javascript:
var array1 = ['S', 'T', 'A', 'C', 'K', 'O', 'V', 'E', 'R', 'F', 'L', 'O', 'W'];
Now I want to replace all the elements at once from index 3 to 9 in following way:
array1 = ['S', 'T', 'A', 'X', 'X', 'X', 'X', 'X', 'X', 'X', 'L', 'O', 'W'];
Is it possible to achieve in javascript ?
Note: I want to perform following operation using array only
Use Array.fill()
var array1 = ['S', 'T', 'A', 'C', 'K', 'O', 'V', 'E', 'R', 'F', 'L', 'O', 'W'];
array1.fill('X', 3, 10)
console.log(array1)Use array splice() method
var array1= ['S', 'T', 'A', 'C', 'K', 'O', 'V', 'E', 'R', 'F', 'L', 'O', 'W'];
// At position 3, delete 7 and add 7 elements:
array1.splice(3, 7, "X","X","X","X","X","X","X");
console.log(array1);
array1.splice(start, end-start, ...Array(end-start).fill("X"));One way is with Array.prototype.map:
This loops through every index of the array, and if the index is between 3 and 9 (inclusive), set it to 'X', otherwise keep it as the original chr (character)
var array1 = ['S', 'T', 'A', 'C', 'K', 'O', 'V', 'E', 'R', 'F', 'L', 'O', 'W'];
var array2 = array1.map((chr, idx) => 3 <= idx && idx <= 9 ? 'X' : chr);
console.log(array2);
array1 = array1.map()It sure does.
const arr = ['a', 'b', 'c', 'd', 'e']
function replaceWithX(start, end) {
for (let i = start; i <= end; i++) {
arr[i] = 'x'
}
}
replaceWithX(1, 3)
console.log(arr) // ["a", "x", "x", "x", "e"]
for loop since OP said: "Note: I want to perform following operation using array only"
array.splice() is a better choice.
array1.forEach((a,b,c)=>array1[b]=(b<9 && b>2)?'X':a);