PHP array get the different number

Question

I have the following array:

$array = [2,2,5,2,2];

I would like to get the number which is different from the others, for example all the numbers are 2 except the number 5. So Is there anyway to get the different number using any array method or better solution? My solution is:

    $array = [2,2,5,2,2];
    $array1 = [4,4,4,6,4,4,4];

    $element = -1;
    $n = -1;
    $count = 0;
    for($i=0; $i<count($array1); $i++) {

        if($element !== $array1[$i] && $element !== -1 & $count==0) {
            $n = $array1[$i];
            $count++;
        }

        $element = $array1[$i];
    }

    dd($n);

You could always just check out the PHP Array Functions page in the manual — RiggsFolly
– RiggsFolly, Commented Nov 2, 2021 at 10:28

Simone Rossaini · Accepted Answer · 2021-11-02 10:35:17Z

4

You can use array_count_values for group and count same value like:

$array = [2,2,5,2,2];
$countarray = array_count_values($array);
arsort($countarray);
$result = array_keys($countarray)[1]; // 5

Since you only have two numbers, you will always have the number with the least equal values in second position

Reference:

A small clarification, for safety it is better to use arsort to set the value in second position because if the smallest number is in first position it will appear as the first value in the array

Sorting Arrays

edited Nov 2, 2021 at 10:35

answered Nov 2, 2021 at 10:29

Simone Rossaini

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Md. Salahuddin · Accepted Answer · 2021-11-02 11:01:28Z

0

You can user array_count_values which returns array with item frequency.

Then use array_filter to filter out data as follow:

 $arrayData = [2,2,2,5];
 $filterData = array_filter(array_count_values($arrayData), function ($value) {
                     return $value == 1;
               });
print_r($filterData);

Inside array_filter(), return $value == 1 means only get the data with 1 frequency and thus filter out the other data.

answered Nov 2, 2021 at 11:01

Md. Salahuddin

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1 Comment

Simone Rossaini Over a year ago

This good work too, the "only problem" is if the smallest count is plus 1

Hamza Zee Khan · Accepted Answer · 2021-11-02 11:36:13Z

<?php
function UniqueAndDuplicat($array){
$counts = array_count_values($array);
foreach ($counts as $number => $count) {
print $number . ' | ' . ($count > 1 ? 'Duplicate value ' : 'Unique value ') . "\n";
 }
}

$array1 = [2,2,5,2,2];
$array2 = [4,4,4,6,4,4,4];
UniqueAndDuplicat($array1);
//output: 2 | duplicate value  5 | Unique value
UniqueAndDuplicat($array2);
//output: 4 | duplicate value  5 | Unique value
?>

Use this function to reuse this you just call this function and pass an Array to this function it will give both unique and duplicate numbers.

If you want to return only Unique number then use the below code:

<?php
function UniqueAndDuplicat($array){
$counts = array_count_values($array);
foreach ($counts as $number => $count) {
if($count == 1){
return $number;
    }
 }
}

$array1 = [2,2,5,2,2];
$array2 = [4,4,4,6,4,4,4];
echo UniqueAndDuplicat($array1); // 5
echo "<br>";
echo UniqueAndDuplicat($array2); // 6
?>

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