Initialize python array, every time it is called, where on of elements is dynamic

Question

I have an array in python:

ARR1 = ['A', 'B', 'C', 'D']

and another array, which uses previous array random value for one of the elements

ARR2 = ['1', '2', '3', random.choice(ARR1)]

when I invoke print(ARR2[]) I get random value on last position and this is fine.

Now I have a for in loop:

for i in range(3):
    print(ARR2[])

and I get the same random value every 3 times, like:

['1', '2', '3', 'B'] ['1', '2', '3', 'B'] ['1', '2', '3', 'B']

What I would like is, 5 random values, like:

['1', '2', '3', 'D'] ['1', '2', '3', 'A'] ['1', '2', '3', 'C']

How I understand it, the array ARR2, would have to be initialized, every time it is called in for loop.

Is it doable in Python?

Tamir · Accepted Answer · 2021-11-20 13:47:45Z

1

You created ARR2 once and it already randomized a value when it was initialised. Simply calling it again won't re-sample a random choice from ARR1

If you want it to generate a random choice each time you should do something like:

import random
ARR1 = ["A", "B", "C", "D"]
for _ in range(3):
   ARR2 = ["1", "2", "3", random.choice(ARR1)]
   print(ARR2)

answered Nov 20, 2021 at 13:47

Tamir

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2 Comments

pc131 Over a year ago

That worked! Nesting ARR2[] creation inside a loop. Thank you @Tamir.

pc131 Over a year ago

I upvoted, not sure how I accept it :-)

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