Filtering an array based on an array of Int

Question

I have a Drink object that has a property called strength. Strength is an Integer with values of 0,1,2 or 3.

Now in my project, I display all of the Drink objects in a List View. At the top of the list view, there's a filtering section for the user to filter the Drink objects based on strength. These are CHECK BOXES, meaning users can select as little as 1 filter, or as much as 4. This gets saved to SharedPreferences as an Int Array.

data class Drink(val theDrinkName:String, val strength:Int)


object DrinkData {

    const val low = 0
    const val medium = 1
    const val strong = 2
    const val intense = 3

    fun generateAllDrinks():Array<Drink> {
        return arrayOf(
            Drink("Vodka", medium),
            Drink("Shirley Temple", low),
            Drink("rum", strong),
            Drink("Gin", medium),
            Drink("151", intense),
            Drink("99", strong)
        )
    }

}

Here's how I am generating all of the data:

val allDrinks = DrinkData.generateAllDrinks().sortedWith(
    compareBy<Drink> { it.theDrinkName.first().isDigit() }
        .thenBy { it.theDrinkName.toLowerCase() }
)

I need to be able to filter the strength property of this data based on an Int Array. (An Int Array is what gets saved to SharedPreferences.)

val filteredStrengthArray = arrayListOf<Int>(2,3)

This would filter allDrinks to rum, 151, 99.

My progress:

This is the closet I got to achieving this filtering.

    val allDrinks = DrinkData.generateAllDrinks().sortedWith(
        compareBy<Drink> { it.theDrinkName.first().isDigit() }
            .thenBy { it.theDrinkName.toLowerCase() }
    ).filter { it.strength == 2 || it.strength == 3 }

The problem is I need to filter by an Int Array to align what is saved in SharedPreferences.

How can I filter the strength property of this data by providing an Int Array?

Jenea Vranceanu · Accepted Answer · 2021-11-22 21:55:19Z

1

The first solution that comes to mind is checking if strength property is contained by filteredStrengthArray:

val filteredStrengthArray = arrayListOf<Int>(2,3)
val allDrinks = DrinkData.generateAllDrinks().sortedWith(
        ...
    ).filter { filteredStrengthArray.isEmpty() || filteredStrengthArray.contains(it.strength) }

answered Nov 22, 2021 at 21:55

Jenea Vranceanu

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