How to access lambda function's value here?

Question

def sum_(f, start, end):
    # 1st_value,_,__ = map(f,[start,end]) # how to get 1st value passed on lambda function here ? 
    # print(1st_value+start+end)
    return
if __name__ == '__main__':
    print(sum_(lambda y: 1.0, 5, 10))) # 1st_value=1.0,2nd_value=5, 3rd_value=10

How can i get 1.0 value from lambda function inside sum_()? I tried map(), but it did not work.

I have gone to other similar questions too, but did not find my answer, so please don't mark it duplicate.

ThePyGuy · Accepted Answer · 2021-11-29 05:46:37Z

2

You need to call the lambda function; you have passed the lambda function to the function sum_, but you are not calling the lambda :

>>> def sum_(f, start, end):
        value = f(None) # Pass value of y
        print(start-end+value)
>>>> sum_(lambda y: 1.0, 5, 10)
-4.0

A side note, 1st_value that you have in commented part of the code is not a valid variable name.

edited Nov 29, 2021 at 5:46

answered Nov 29, 2021 at 5:42

ThePyGuy

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4 Comments

Abhishek soni Over a year ago

When i try that It gives a type error: 'tuple' object is not callable

ThePyGuy Over a year ago

@Abhisheksoni, the solution now has the modified version of your code. It is working fine! Give it a try

Abhishek soni Over a year ago

thanks that above piece of code works but why this is not working then ? f = lambda y: 1.0, 5, 10 print(f(None) )

ThePyGuy Over a year ago

` f = lambda y: 1.0, 5, 10` creates a tuple, and the first item in the tuple contains lambda function, it will work if you call first item in this tuple by: f[0](None)

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