In a php script I am receiving some data:
$data = $_POST['someData'];
How can I do something like this:
goToThisUrl( "http://someDomain.com/someScript.php?data = ".$data );
or if it is easier how can I do it by POST?
BTW. This is not happening in a browser, the first php script is getting called by a cart when the order is paid for (if it makes any difference)
Replace goToThisUrl with the real function file_get_contents and remember to urlencode($data) and that would work just fine.
If you want to POST the data instead, look at cURL. Typing "[php] curl post" into the search box will get you the code.
file_get_contents using stream_context_create, which is far simpler than cURL.If you want to send the user there, then:
header('Location: http://someDomain.com/someScript.php?data='.$data);
exit;
Or if you just want to call the other server, you can do:
$response = file_get_contents('http://someDomain.com/someScript.php?data='.$data);
Both assume data is already a urlencoded string, you might want to use 'data=' . urlencode($data) or just http_build_query($data) otherwise.
foreach ($_POST as $key => $val) {
$qs = urlencode($key) . "=" . urlencode($val) . "&";
}
$base_url = "<url here>";
$url = $base_url . "?" . $qs;
header('Location: $url'); exit();
urlencode($val) in the loop and not the entire query string and it'd be good. As is, you destroy the query string by encoding the = and & symbols.urlencode($key) to be safe, or simply $qs = http_build_query($_POST);
someScript.phpis on the same domain, it would be a lot easier to include it usingrequireand simply call the functions directly.