How can I use a Python list (e.g. params = ['a',3.4,None]) as parameters to a function, e.g.:
def some_func(a_char,a_float,a_something):
# do stuff
-
Related: Python 3 Annotations: Type hinting a list of a specified type (PyCharm)Stevoisiak– Stevoisiak2018-02-27 20:36:20 +00:00Commented Feb 27, 2018 at 20:36
Add a comment
|
4 Answers
You can do this using the splat operator:
some_func(*params)
This causes the function to receive each list item as a separate parameter. There's a description here: http://docs.python.org/tutorial/controlflow.html#unpacking-argument-lists
Comments
This has already been answered perfectly, but since I just came to this page and did not understand immediately I am just going to add a simple but complete example.
def some_func(a_char, a_float, a_something):
print a_char
params = ['a', 3.4, None]
some_func(*params)
>> a
Comments
Use an asterisk:
some_func(*params)
1 Comment
inspectorG4dget
Along those lines, you can also use a dictionary: def f(a, b, c): #do stuff. mydict = {'a':1, 'b':2, 'c':3} f(**mydict)
You want the argument unpacking operator *.
