How to search for a string within an array substring

Question

I have an array like this.If atleast one of the substrings within the array have the value i'm searching for it should pass.

Value1 = [
  "Grape | 100 |Food Catering Service",
  "Apple | 100,000m |Food Catering Service",
  "Water Melon | 100,000m |Catering Service Outside",
  "100,000m |Food Catering Service Outside
]

Using typescript i'm trying to make sure that atleast if a substring in the array there is the value Food. Even though the third substring within this arrat has no food it should still pass.

Code i've tried so far but does not do the job. It just returns the array

export function arraySubstring (expected:string, ignoreCase?: boolean): Expectation<string[], string> {
 return Expectation.that("test", expected, 
    async(actor: Actor, actual: string[]): Promise<boolean> ==> {

  try {
   for (const value of actual) {
     if(ignoreCase) {
       if (!value.toLowerCase().includes(expected.toLowerCase())) return 
         false;
     } else {
         if (!value.includes(expected)) return false;
     }
  }
  return true;
})
}

const value2= await webActor.attemptsTo(Ensure.that("my expectation", 
value1, arraySubstring ("Food")))

Please edit your question to show us the output you need. Your written spec is not quite clear. — O. Jones
– O. Jones, Commented Dec 21, 2021 at 23:57
@O.Jones is that more explanatory. So if i declare that const value2. if it compares the array value1 and Food. My assertion should be true — wyatt brandon
– wyatt brandon, Commented Dec 22, 2021 at 0:20
Also please remember to properly indent your code, because you want people to be able to easily read your code. — Mike 'Pomax' Kamermans
– Mike 'Pomax' Kamermans, Commented Dec 22, 2021 at 0:20
@charlietfl if atleast one of the substrings within the array have the value i'm searching for it should pass. Since atleast 3 have it then it should pass. — wyatt brandon
– wyatt brandon, Commented Dec 22, 2021 at 0:25

S. Stumm · Accepted Answer · 2021-12-22 01:50:09Z

2

Your code relies on it's order. If the first element that gets looped contains no "food", it will return false. Return statements always exit the function.

I'd suggest to create a single string and check the index of the first occurance with indexOf("food"), something like that.

const array = [
  "Grape | 100 |Food Catering Service",
  "Apple | 100,000m |Food Catering Service",
  "Water Melon | 100,000m |Catering Service Outside",
  "100,000m |Food Catering Service Outside",
];

const found = array
  .reduce((obj, entry) => obj.concat(entry))
  .toLocaleLowerCase()
  .indexOf("food");
if (found >= 0) {
  console.log("Array contains food");
} else {
  console.log("Array does not contain food");
}

If you want to iterate you need to return on the true case, this will remove the importance of order from your code.

const array = [
  "Grape | 100 |Food Catering Service",
  "Apple | 100,000m |Food Catering Service",
  "Water Melon | 100,000m |Catering Service Outside",
  "100,000m |Food Catering Service Outside",
];

const ignoreCase = true;
const expected = "Food";

const containsExptected = (_array) => {
  for (const value of _array) {
    if (ignoreCase) {
      if (value.toLowerCase().indexOf(expected.toLowerCase()) >= 0) return true
    } else {
      if (value.indexOf(expected) >= 0) return true;
    }
  }
  return false;
};

const found = containsExptected(array);
if (found) {
  console.log("Array contains food");
} else {
  console.log("Array does not contain food");
}

edited Dec 22, 2021 at 1:50

answered Dec 22, 2021 at 0:57

S. Stumm

2901 silver badge9 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Deepak Over a year ago

Isn't it >=0 instead of >0?

wyatt brandon Over a year ago

Thanks@Deepak i fixed that in my code

Deepak · Accepted Answer · 2021-12-22 01:46:45Z

0

Here's a one-liner to check for a match of substring in an array of strings:

const value = ["Grape | 100 |Food Catering Service", "Apple | 100,000m |Food Catering Service", "Water Melon | 100,000m |Catering Service Outside", "100,000m |Food Catering Service Outside"]

const expected = "Food"
const ignoreCase = true
console.log(value.some(val => (ignoreCase ? val.toLowerCase().includes(expected.toLowerCase()) : val.includes(expected))))

answered Dec 22, 2021 at 1:46

Deepak

2,7522 gold badges13 silver badges31 bronze badges

Collectives™ on Stack Overflow

How to search for a string within an array substring

2 Answers 2

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related