Suppose I have a string,
a="This is a string"
and an array,
b=("This is my" "sstring")
I want to execute an if condition if any substring of a lies in b which is true because "This is" is a substring of the first element of b.
In case of two strings I know how to check if $x is a substring of $y using,
if [[ $y == *$x* ]]; then
#Something
fi
but since $x is an array of strings I don't know how to do it without having to explicitly loop through the array.
This might be all you need:
$ printf '%s\n' "${b[@]}" | grep -wFf <(tr ' ' $'\n' <<<"$a")
This is my
Otherwise - a shell is a tool to manipulate files/processes and sequence calls to tools. The guys who invented shell also invented awk for shell to call to manipulate text. What you're trying to do is manipulate text so there's a good chance you should be using awk instead of shell for whatever it is you're doing that this task is a part of.
$ printf '%s\n' "${b[@]}" |
awk -v a="$a" '
BEGIN { split(a,words) }
{ for (i in words) if (index($0,words[i])) { print; f=1; exit} }
END { exit !f }
'
This is my
The above assumes a doesn't contain any backslashes, if it can then use this instead:
printf '%s\n' "${b[@]}" | a="$a" awk 'BEGIN{split(ENVIRON["a"],words)} ...'
If any element in b can contain newlines then:
printf '%s\0' "${b[@]}" | a="$a" awk -v RS='\0' 'BEGIN{split(ENVIRON["a"],words)} ...'
Here is how to match the maximum number of words from string a to entries of array b:
#!/usr/bin/env bash
a="this is a string"
b=("this is my" "string" )
# tokenize a words into an array
read -ra a_words <<<"$a"
match()
{
# iterate entries of array b
for e in "${b[@]}"; do
# tokenize entry words into an array
read -ra e_words <<<"$e"
# initialize counter/length to the shortest MIN words count
i=$(( ${#a_words[@]} < ${#e_words[@]} ? ${#a_words[@]} : ${#e_words[@]} ))
# iterate matching decreasing number of words
while [ 0 -lt "$i" ]; do
# return true it matches
[ "${e_words[*]::$i}" = "${a_words[*]::$i}" ] && return
# decrease number of words to match
i=$(( i - 1 ))
done
done
# reaching here means no match found, return false
return 1
}
if match; then
printf %s\\n 'It matches!'
fi
You can split the $a into an array, then loop both arrays to find matches:
a="this is a string"
b=( "this is my" "string")
# Make an array by splitting $a on spaces
IFS=' ' read -ra aarr <<< "$a"
for i in "${aarr[@]}"
do
for j in "${b[@]}"
do
if [[ $j == *"$i"* ]]; then
echo "Match: $i : $j"
break
fi
done
done
# Match: this : this is my
# Match: is : this is my
# Match: string : string
If you need to handle substrings in $a (e.g. this is, is my etc) then you will need to loop over the array, generating all possible substrings:
for (( length=1; length <= "${#aarr[@]}"; ++length )); do
for (( start=0; start + length <= "${#aarr[@]}"; ++start )); do
substr="${aarr[@]:start:length}"
for j in "${b[@]}"; do
if [[ $j == *"${substr}"* ]]; then
echo "Match: $substr : $j"
break
fi
done
done
done
# Match: this : this is my
# Match: is : this is my
# Match: string : string
# Match: this is : this is my
iis in them? Is the double s in sstring a typo?ais a substring of "This is my" of the first element ofb, I want a match to occur. The double s is not a typo. I don't want a match by string being a substring of sstring. I am looking for matches only upto words separated by a space.aandb-- according to your comment, you're only looking for space-separated substrings ofa. Does this also apply for matches inb? For example should an entry like "banapple gas" inbmatch, sinceais a space-separated substring ina?ais a substring of any element ofb? Because I would ordinarily be inclined to interpret "lies in [array]b" as "is equal to an element ofb", yet that is not consistent with your example. Note also that your[[ $a == *${b[0]}* ]]would evaluate to false with your example data.