Get only file name in variable in a for loop

Question

I have a for loop that writes text in a file :

for f in $DATA_DIRECTORY 
do 
    echo ' input.'$f '{'
    echo '  copy = ${source.copy}"'$f'.CPY"'
    echo '  data = ${source.data}"'$f'.CSV"'
    echo ' }'
done

But the "f" variable here looks like this :

/path/to/my/file/FILE.TXT

What i want to get is only the name of the file, not the full path and its extension:

FILE

By the way i tried to change my f variable like this so i dont get the extension but it did not work :

{$f%%.*}

chepner · Accepted Answer · 2022-01-07 16:27:29Z

5

You need two lines; chained operators aren't allowed.

f=${f##*/}  # Strip the directory
f=${f%%.*}  # Strip the extensions

Or, you can use the basename command to strip the directory and one extension (assuming you know what it is) in one line.

f=$(basename "$f" .txt)

answered Jan 7, 2022 at 16:27

chepner

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