Python nested functions

Question

Absolutely newbie in Python. Statement is satisfied as user exist in DB so program prints "DETAILS CORRECT" but also I would like it to jump to next window (made in PyQt5) by going through next function. Is that correct? def function2

    else:
        cur = conn.cursor()
        query = 'SELECT customer_password FROM customers_table WHERE customer_login =\'' + customerlogin + "\'"
        cur.execute(query)
        result_pass = cur.fetchone()[0]
        if result_pass == customerpassword:
            def function2():   
        self.errorlabel.setText("DETAILS CORRECT")
        else:
            self.errorlabel.setText("PLEASE CHECK DATA OR REGISTER")

What is your issue regarding the code? Does it work according to your expectation? — raiyan22
– raiyan22, Commented Jan 17, 2022 at 21:37

Mohammad · Accepted Answer · 2022-01-17 21:37:46Z

2

You need to call the function not define it, you define it somewhere else:

def func2():
    ...

...

if result_pass == customerpassword:
    self.errorlabel.setText("DETAILS CORRECT")
    func2()     
else:
    self.errorlabel.setText("PLEASE CHECK DATA OR REGISTER")

answered Jan 17, 2022 at 21:37

Mohammad

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