how to iterate over date using for loop in python

Question

I am creating an app where I have two values, a committee starting date for e-g 2022,01,02 and for how many months it will continue here it is (4months). Now I am saving some data in my database month wise and also these dates will save too. now the issue is I am getting right result if the number of month is less than or equal to 12 using this.

number of memebrs = 12
starting date = 2022,01,01
for i in range(1,17):
      print('date', (2022,i,10))

but the issue comes when the months are greater than 12 so than date start printing 2022,01,13 which is false because I also want to increment the year to 2023, I feel like this is not really a good idea very inefficient looking way. can anyone tell me is there any other way to do this.

Apart from the fact that your code is invalid Python, what stops you from simply incrementing the year and resetting the month to 1 when you see that the month is 12? — Marco Bonelli
– Marco Bonelli, Commented Jan 18, 2022 at 18:20
You will want to add an if like this: if i%12 == 0: year += 1 and you will probably want to use a while loop so that you can reset i when needed. — Eli Harold
– Eli Harold, Commented Jan 18, 2022 at 18:23
@cesarv Yes I am thinking of finding some way of using the lib. My approach doesn't look good. — Music Cause
– Music Cause, Commented Jan 18, 2022 at 18:27

Aryav Bhola · Accepted Answer · 2022-01-18 21:48:29Z

2

By the tone of your question i think you are a beginner, so i won't recommend you to use datetime module and i appreciate that you tried to do it on your own. What i dont appreciate is that why cant you just use if statements and create variables for year and date

yr = 2022
dt = 1
for i in range(1,17):
  print('date', (yr,i,dt))
  if i % 12 == 0:
    yr += 1
    mn = 1

I also want to share the modern aproach using datetime module. But it requires some modules.

In your cmd enter the command pip install python-dateutil

Once installed close cmd and refresh your ide

this is the code you may want to use

from datetime import datetime
from dateutil.relativedelta import relativedelta

date_time = datetime(2022, 1, 1) #Creating a Date object

for i in range(1, 17):
    date = date_time.date()
    print(date)
    date_time = date_time + relativedelta(months=1)

edited Jan 18, 2022 at 21:48

answered Jan 18, 2022 at 18:32

Aryav Bhola

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user17903384 · Accepted Answer · 2022-01-18 18:48:56Z

1

While you can use the datetime library to handle dates, it doesn't provide any methods to increase dates month by month.

Now, previous suggestions/answers suggest you increase the year when month == 12, but that will cause December to be skipped. Also, your code doesn't consider any given month in the starting date. So a better solution would be:

>>> year = 2022
>>> month = 7
>>> day = 23
>>>
>>> for i in range(1, 8):
...     month += 1
...     if month == 13:
...         month = 1
...         year += 1
...     print(f'{year}-{month}-{day}')
...
2022-8-23
2022-9-23
2022-10-23
2022-11-23
2022-12-23
2023-1-23
2023-2-23

answered Jan 18, 2022 at 18:48

user17903384

Comments

XxJames07- · Accepted Answer · 2022-01-18 18:29:19Z

1

you could do something like this:

date = [2022,1,10]
for i in range(1,17):
    if i%12==0:
        date[0]+=1
        date[1]=1
    print('date', (time[0],i,time[2]))

answered Jan 18, 2022 at 18:29

XxJames07-

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