Filter multidimensional array based on another array

Question

I am new to JS. I have multidimensional array.

var myList = [{"Fund":"Edelweiss1","Rank":10},{"Fund":"Edelweiss","Rank":5}, {"Fund":"Edelweiss3","Rank":3}]

I want to filter "Rank" based on another array.

var rngarray = [6,10];

Filtering on rank should be >=6 and <=10

I tried this - myList.filter(function (v) {rngarray.includes(v["Rank"])}) but does not work.

Wais Kamal · Accepted Answer · 2022-01-19 21:16:42Z

1

Use Array.prototype.filter():

var myList = [{"Fund":"Edelweiss1","Rank":10},{"Fund":"Edelweiss","Rank":5}, {"Fund":"Edelweiss3","Rank":3}];

var rngarray = [6,10];

var filtered = myList.filter(item => item.Rank >= rngarray[0] && item.Rank <= rngarray[1]);
console.log(filtered);

edited Jan 19, 2022 at 21:16

answered Jan 19, 2022 at 9:28

Wais Kamal

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2 Comments

Ujjawal Bhandari Over a year ago

Thanks. Works like a charm. Can you please explain why this does not work - myList.filter(function (v) {v.Rank >= rngarray[0] && v.Rank <= rngarray[1]})

fdomn-m Over a year ago

myList.filter(function (v) {v.Rank > when you use function you need a return: myList.filter(function (v) { return v.Rank > - when using item => without { the return is implied.

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