Using regex to extract index of the element from the list and retrieve value

Question

I have a list of strings, below is just one example:

str_list = ['Navitas', 'Organic Cacao Powder', '227g', 'SALE $7.49 ea', 'Regular $9:99-ea', 'Valid 01/12 - 01/18']

I want to extract the '227g' element based on finding the index.

unit_index = [idx for idx, val in enumerate(str_list) if val.endswith((' ml','-pack','{\d}g', ' L'))]

But this doesn't seem to work. I would like to find out where it ends with a digit followed by a unit of measure (ml, g, L)

Maybe just filter with re.search(r'(?: ml|-pack|\d+g)$', val)? Or see ideone.com/L3xL1L — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jan 24, 2022 at 0:30

skara9 · Accepted Answer · 2022-01-24 02:40:29Z

2

You can use \d+\s?(ml|-pack|g|L)$ to check for a number with a unit after it.

import re

str_list = ['Navitas', 'Organic Cacao Powder', '227g', 'SALE $7.49 ea', 'Regular $9:99-ea', 'Valid 01/12 - 01/18']
r = r"\d+\s?(ml|-pack|g|L)$"
unit_index = [idx for idx, val in enumerate(str_list) if re.search(r, val)][0]

answered Jan 24, 2022 at 2:40

skara9

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