Java Generics: Compilation failure when using Stream.toArray()

Question

Given a simple generic class:

private static class Container<T> {
    private List<T> aList;
    private T aValue;

    private Container(List<T> aList, T aValue) {
        this.aList = aList;
        this.aValue = aValue;
    }
}

Initialize a list of that class:

List<Container<?>> container = new ArrayList<>();
// Add some elements...

Not possible (The method toArray(IntFunction<A[]>) in the type Stream<List<capture#1-of ?>> is not applicable for the arguments (List<?>[])):

container.stream().map(value -> value.aList).toArray(new List<?>[0]);

Possible:

container.stream().map(value -> value.aList).collect(Collectors.toList()).toArray(new List<?>[0]);

Why?

Eran · Accepted Answer · 2022-01-26 10:15:09Z

1

Stream's toArray takes a IntFunction<A[]> - i.e. a function that accepts an int and returns an array.

You tried to pass an array to it.

It should be used as follows:

container.stream().map(value -> value.aList).toArray(List<?>[]::new)

answered Jan 26, 2022 at 10:15

Eran

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