Why did value of string integer changed when putting it into int array?

Question

Scanner input = new Scanner(System.in);
    System.out.println("How many numbers will you enter?");
    int x = input.nextInt();
    input.nextLine();
    int[] array = new int[x];
    
    System.out.println("Enter " + x + " integers, one per line:");
    Integer y = input.nextInt();
    input.nextLine();
    String z = y.toString();
    
    for (int i = 0; i < array.length; i++) {
        array[i] = z.charAt(i);
        System.out.println(z.charAt(i));
    }
    for (int i = 0; i < array.length; i++) {
        System.out.println(array[i]);
    }

I put 1 to feed into the array and when I printed it, it got printed 49 instead.

Louis Wasserman · Accepted Answer · 2022-01-27 05:55:45Z

3

You put a char into an int array, and you got the expected result -- which is the ASCII value of the character '1', or 49.

What you want to do for your use case is to use Integer.parseInt on the String of the entire line, not to try to convert the individual characters.

answered Jan 27, 2022 at 5:55

Louis Wasserman

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