zend_json an array that contains objects

Question

so suppose I have this

$arr = array(some object with property a,b,c,d,etc);

and you call Zend_Json::encode($arr);

instead of encoding the object within it as well, it will just return an encoded empty array: [{}]

which is an epic fail

how do I tell Zend_Json to also encode the object within the array and not just return this failure

##################### EDIT

alright so I actually have this method in the class:

public function toJson(){
    $params = get_object_vars($this);
    return Zend_Json::encode($params);
}

yet it's still only outputting an empty array

[{}]

encoding the object itself works, but not if it's inside an array

...

Are they protected or private properties?

David Snabel-Caunt
– David Snabel-Caunt

2011-08-17 09:46:44 +00:00
Commented Aug 17, 2011 at 9:46 — David Snabel-Caunt
– David Snabel-Caunt, Commented Aug 17, 2011 at 9:46

Hari K T · Accepted Answer · 2011-08-18 05:36:33Z

2

If you are encoding PHP objects by default the encoding mechanism can only access public properties of these objects. When a method toJson() is implemented on an object to encode, Zend_Json calls this method and expects the object to return a JSON representation of its internal state.

http://framework.zend.com/manual/en/zend.json.advanced.html#zend.json.advanced.objects2

Update : This is the piece of code I tried. And it works fine, I feel your object properties has no values.

class Hello 
{
    private $hello = 'Hello';
    public $wolrd = ' World';

    public function getProperties()
    {
            return get_object_vars($this);
    }

}
$json = new Zend_Json();
$hello = new Hello();
echo $json->encode( array( $hello->getProperties() ) );

Result :

[{"hello":"Hello","wolrd":" World"}]

Hope fully this will work. Some thoughts from the post ;) http://blog.calevans.com/2008/02/21/zend_jsonencode-and-wth-are-all-my-properties/

edited Aug 18, 2011 at 5:36

answered Aug 17, 2011 at 10:40

Hari K T

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1 Comment

David Snabel-Caunt Over a year ago

+1, a simple implementation of toJson can just simply create a new stdClass, copy the value of non-public properties to this object and then return Zend_Json::encode(myValueObject);

Krystian Krasowski · Accepted Answer · 2013-07-26 09:31:52Z

0

By default Zend_Json::encode method uses PHP json_encode function. You need to set Zend_Json::$useBuiltinEncoderDecoder to true and implement a toJson method in your domain object which is in your array. This method should return valid json string.

class Foo
{
    private $a;
    private $b;

    public function toJson()
    {
        return $json = Zend_Json::encode(array(
            'a' => $this->a;
            'b' => $this->b
        ));
    }
}
Zend_Json::$useBuiltinEncoderDecoder = true;
echo Zend_Json::encode(array(new Foo()));

answered Jul 26, 2013 at 9:31

Krystian Krasowski

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