Python: converting list of strings into a string which illustrates the list

Question

I'm searching a simple method for converting a list of strings (e.g. ['test 1', 'test 2' , 'test 3'] ) into a string whereby the list of objects doesn't have some quotation mark. That means in our example ('[test 1, test 2, test 3]'). My first approach was:

import json
A = ['test 1', 'test 2' , 'test 3']
test = json.dumps(A).replace('"', '')

Is their a more general way without that replace statement at the background? Cause my problem with that is, that e.g.

A = ['test 1', 'test 2' , 'test 3"AA"']

results in the string:

   '[test 1, test 2, test 3\AA\]'

and not the desired string:

'[test 1, test 2, test 3"AA"]'

Corralien · Accepted Answer · 2022-01-29 11:43:19Z

4

Try f-strings:

>>> print(f"'[{', '.join(A)}]'")
'[test 1, test 2, test 3"AA"]'

# OR

>>> print(f"[{', '.join(A)}]")
[test 1, test 2, test 3"AA"]

answered Jan 29, 2022 at 11:43

Corralien

121k8 gold badges44 silver badges69 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

SpacedOutKID · Accepted Answer · 2022-01-29 11:52:59Z

2

A simple way you could try would be

A = ['test 1', 'test 2' , 'test 3"AA"'] #your list
print (*A, sep =', ')

answered Jan 29, 2022 at 11:52

SpacedOutKID

1551 gold badge1 silver badge15 bronze badges

Collectives™ on Stack Overflow

Python: converting list of strings into a string which illustrates the list

2 Answers 2

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related