I have an array a = [4,3,2,1]
What I am trying to achieve is that I need a single value on subtracting the elements in the array that is 4-3-2-1.
I tried the below this using for loop but it does not seem to work. I don't seem to get the right value on execution.
def sub_num(arr):
difference = arr[0]
n = len(arr)
print(n)
print(i)
for i in n: difference = arr[n] - arr[n-1]
return(difference)
If you have a list a:
a = [4, 3, 2, 1]
And wish to get the result of 4 - 3 - 2 - 1, you can use functools.reduce.
>>> from functools import reduce
>>> a = [4, 3, 2, 1]
>>> reduce(int.__sub__, a)
-2
>>>
You can solve with nested lists:
b = sum([a[0],*[-x for x in a[1:]]])
Simpler solution without for:
Since 4-3-2-1 is equal to 4-(3+2+1):
a[0]-sum(a[1:])
You could modify your code like this
def sub_num(arr):
difference = arr[0]
n = len(arr)
print(n)
for i in range(1,n):
difference = difference - arr[i]
return difference
Note:
4 - 3 - 2 - 1be-2?