I am practicing with for in loops and having trouble with this.
places = ["phuket", "athens", "doha"]
for places in range(5):
if places == 0:
print("thailand," + places 0 + "is a cool place")
else:
print("not thailand")
When I try this, I get a syntax error with 'places 0'. I want it to print thailand, phuket, is a cool place. But no matter how I seem to format places 0 (with the 0 in [], with it in ()) I just keep getting syntax errors.
Use places[0] and name your for loop variable something other than places so that you don't have conflicting names, eg: for i in range(5) is a more standard naming convention – - Nick Parsons. This was the correct answer:
places = ["phuket", "athens", "doha"]
for index in range(5):
if index == 0:
print("thailand, " + places[0] + "is a cool place")
else:
print("not thailand")
If you use enumerate you can get the index of the for loop. i will be 0, 1, 2 and place will be phuket, athens, doha. And you can use different logic depends on what you want.
places = ["phuket", "athens", "doha"]
for i,place in enumerate(places):
if i == 0:
print("thailand," + place + "is a cool place")
else:
print("not thailand")
You can understand more here - https://realpython.com/python-enumerate/
You would need to use the places list in the for loop, as well as use the correct syntax for checking the if condition:
places = ["phuket", "athens", "doha"]
for place in places:
if place == "phuket":
print("thailand, " + place + " is a cool place")
else:
print("not thailand")
When you use this for syntax it returns the value and not the index so your test should be
if place == "phuket":
for places in range(5):, places is the "index", not the value. You seem to be thinking of for place in places: ?
Two simplest methods are below which can solve you problem easily:
Ist method
IInd method
places[0]and name yourforloop variable something other thanplacesso that you don't have conflicting names, eg:for i in range(5)is a more standard naming convention