ANDROID StringEntity fail inside eclipse

Question

Sorry about this simple(?) question but I'm a newbie on java and android.

First I have this import section.

import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;
import android.view.View.OnClickListener;

import java.util.List;
import java.util.ArrayList; 

import java.io.InputStream;
import java.io.InputStreamReader;

import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.ResponseHandler;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.HttpResponse;
import org.apache.http.HttpEntity;
import org.apache.http.message.BasicNameValuePair;  
import org.apache.http.protocol.HTTP;
import org.apache.http.NameValuePair;
import org.apache.http.entity.*;
import org.apache.http.impl.client.BasicResponseHandler;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.entity.StringEntity;

import org.apache.http.client.entity.UrlEncodedFormEntity;

Then I have this code.

            String s = new String();
            // Handle successful scan

            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost(URL);

            s += "enter=<eanrequest><ean>";
            s += contents;
            s += "</ean></eanrequest>";             

        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);   
            nameValuePairs.add(new BasicNameValuePair("enter", s));

            ean.setText(s);

            HttpEntity se = new StringEntity(s);  //When I hold the mouse over this I get "Unhandled exception type UnsupportedEncodingException".

What am I doing wrong?

/Erik

Do you mean after the imports you just have the code you posted, without any class!? (anyway, the imports part is not relevant at all for a queston, you can always just go to Source-Organize Imports, and Eclipse will take care of them for you) — Adinia
– Adinia, Commented Aug 18, 2011 at 8:59
So, if you also have a class/activity beside the code you posted, from the message you get, I think it just want you to wrap that line in a try/catch block. — Adinia
– Adinia, Commented Aug 18, 2011 at 9:12

mario595 · Accepted Answer · 2014-03-12 09:22:03Z

1

Try with:

try{
    HttpEntity se = new StringEntity(s);
}catch(Exception e){

}

The StringEntity constructor can throw an exception that you have to handle. You can either wrap it in a try/catch block or declare that your method can throw an exception:

public void myMethod() throws Exception{
    //...
    HttpEntity se = new StringEntity(s);
    //...
}

answered Mar 12, 2014 at 9:22

mario595

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