How to check the specific element in string are equal in python?

Question

There is a two input first input represent the index of the second input.I need to find the 'X' position of second input are same or not?

input:

123X56XX
Ahjutruu

Output:
  True

Example: X in input one at 4,7,8

position of 4,7,8 in second input is 'u' all are same so i need to print "true"

I tried using enumerate function but not came:

a="123X56XX"
b="Ahjutruu"
xi=[]

for i,val in enumerate(a):
  if val=='X':
    xi.append(i)
print(xi)  
#next step only i dont know how to doo please help

Next i dont know how to check

S4eed3sm · Accepted Answer · 2022-02-12 07:00:32Z

5

Put all values of given indexes of xi in set, the length of this set must equal to 1:

xi = [i for i, c in enumerate(a) if c == 'X']
len(set([b[i] for i in xi])) == 1

edited Feb 12, 2022 at 7:00

answered Feb 12, 2022 at 6:55

S4eed3sm

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1 Comment

Corralien Over a year ago

Please add: xi = [i for i, c in enumerate(a) if c == 'X']

Wrench · Accepted Answer · 2022-02-12 07:01:49Z

5

you can do like this

a = "123X56XX"
b = "Ahjutruu"

status = len({j for i,j in zip(a,b) if i=='X'}) == 1
print(status)

edited Feb 12, 2022 at 7:01

answered Feb 12, 2022 at 6:55

Wrench

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4 Comments

user8234870 Over a year ago

solution is awesome please add some explanation

Wrench Over a year ago

Considering a and b have same length, first we will iterate both of that with zip. Using zip you can iterate multiple iterators. While checking the strings, make a set of elements of b it the element of a with same index has 'x'. Now obviously the set will make every element unique, so if position 'x' has same character then the set will be only one unique char. The length is 1. If they have more than one number then the set length will be more than 1.

user7864386 Over a year ago

this is the best answer here

Kelly Bundy Over a year ago

Now you just need to not assume that there are any X.

Orius · Accepted Answer · 2022-02-12 07:00:34Z

3

An optional solution:

a="123X56XX"
b="Ahjutruu"

c = list([b[i] for i in range(len(a)) if a[i] == "X"]) # a sublist of the characters from b that correspond to "X" in a
s = set(c) # a set with the elements of c; a set has no duplicated elements, so if all of c's items are the same, s will only have one element
print(len(s) == 1)

answered Feb 12, 2022 at 7:00

Orius

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1 Comment

Orius Over a year ago

@Heisenberg You're welcome!

user8234870 · Accepted Answer · 2022-02-12 06:55:51Z

1

the logic is added for matching the X places in a

a = "123X56XX"
b = "Ahjutruu"
xi = []
allSame = True
for i, val in enumerate(a):
    if val == 'X':
        xi.append(i)#saving the indices
allSame = len(a) == len(b)  # length must be same
prev = None
for v in xi:
    if not allSame:
        break
    if prev is None:
        prev = b[v]  # if previous value is not set setting it
    else:
        allSame = prev == b[v]  # matching with previous value in b's list

print(allSame)

answered Feb 12, 2022 at 6:55

user8234870

Comments

Shreyas Singh · Accepted Answer · 2022-02-12 07:10:50Z

1

Minor addition to your code.

a="123X56XX"
b="Ahjutruu"
xi=[]
result = False
for i,val in enumerate(a):
  if val=='X':
    xi.append(i)
print(xi[0])

for index, value in enumerate(xi):
    if index < len(xi) - 1:
        if b[value] == b[xi[index+1]]:
            result = True
        else:
            result = False
print(result)

answered Feb 12, 2022 at 7:10

Shreyas Singh

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1 Comment

Shreyas Singh Over a year ago

@Heisenberg. Anytime.

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