How do I set each bit in the following byte array which has 21 bytes or 168 bits to either zero or one?
byte[] logonHours
Thank you very much
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3 Answers
Well, to clear every bit to zero you can just use Array.Clear:
Array.Clear(logonHours, 0, logonHours.Length);
Setting each bit is slightly harder:
for (int i = 0; i < logonHours.Length; i++)
{
logonHours[i] = 0xff;
}
If you find yourself filling an array often, you could write an extension method:
public static void FillArray<T>(this T[] array, T value)
{
// TODO: Validation
for (int i = 0; i < array.Length; i++)
{
array[i] = value;
}
}
Comments
System.Collections.BitArray a = new System.Collections.BitArray(logonHours);
a.SetAll(true);
Note that this copies the data from the byte array. It's not just a wrapper around it.
Comments
This may be more than you need, but ...
Usually when dealing with individual bits in any data type, I define a const for each bit position, then use the binary operators |, &, and ^.
i.e.
const byte bit1 = 1;
const byte bit2 = 2;
const byte bit3 = 4;
const byte bit4 = 8;
.
.
const byte bit8 = 128;
Then you can turn whatever bits you want on and off using the bit operations.
byte byTest = 0;
byTest = byTest | bit4;
would turn bit 4 on but leave the rest untouched.
You would use the & and ^ to turn them off or do more complex exercises.
Obviously, since you only want to turn all bits up or down then you can just set the byte to 0 or 255. That would turn them all off or on.
