I have tried the below solution for question2 to get result2. What would be a more efficient way to get both the result (result1, result2 & result3) with the same code?
question1 = [
{
"groupName": "Group 1",
"id": "group1",
"options": [
{
"name": "Cat1",
"selected": true
},
{
"name": "Cat2",
"selected": true
},
{
"name": "Cat3",
"selected": false
},
{
"name": "Cat4",
"selected": false
}
]
},
{
"groupName": "Group 2",
"id": "Brand",
"options": [
{
"name": "brand1",
"selected": false
},
{
"name": "brand2",
"selected": true
},
{
"name": "brand3",
"selected": false
}
]
},
{
"groupName": "Group 3",
"id": "Price",
"options": [
{
"name": "$0 - $9",
"selected": false
},
{
"name": "$9 - $19",
"selected": false
},
{
"name": "$20 - $29",
"selected": false
}
],
"range": {
"min": 5,
"max": 20
}
}
]
result1 = [{
"groupName": "Group 1",
"id": "group1",
"name": "Cat1",
},
{
"groupName": "Group 1",
"id": "group1",
"name": "Cat2",
},
{
"groupName": "Group 2",
"id": "Brand",
"name": "brand2",
},
{
"groupName": "Group 3",
"id": "Price",
"min": 5,
"max": 20
}
]
I have a solution for question2, although I know it's not very efficient, so what could be a better solution?
question2 = [
{
"groupName": "Group 1",
"id": "group1",
"options": [
{
"name": "Cat1",
"selected": true
},
{
"name": "Cat2",
"selected": false
},
{
"name": "Cat3",
"selected": false
},
{
"name": "Cat4",
"selected": false
}
]
},
{
"groupName": "Group 2",
"id": "Brand",
"options": [
{
"name": "brand1",
"selected": false
},
{
"name": "brand2",
"selected": true
},
{
"name": "brand3",
"selected": false
}
]
},
{
"groupName": "Group 3",
"id": "Price",
"options": [
{
"name": "$0 - $9",
"selected": true
},
{
"name": "$9 - $19",
"selected": false
},
{
"name": "$20 - $29",
"selected": false
}
],
"range": {
"min": null,
"max": null
}
}
]
const selected2 = question2.map(group => group.options.filter(option => option.selected).map(option => ({groupName: group.groupName, id: group.id, name: option.name}))).flat(1)
console.log(selected2)
For question3, group 1, none of the options is selected and correspondingly I should get result3. So, only if any of the options are selected or the price has a range (either min/max/both min&max), it is displayed in the result.
question3 = [
{
"groupName": "Group 1",
"id": "group1",
"options": [
{
"name": "Cat1",
"selected": false
},
{
"name": "Cat2",
"selected": false
},
{
"name": "Cat3",
"selected": false
},
{
"name": "Cat4",
"selected": false
}
]
},
{
"groupName": "Group 2",
"id": "Brand",
"options": [
{
"name": "brand1",
"selected": false
},
{
"name": "brand2",
"selected": true
},
{
"name": "brand3",
"selected": false
}
]
},
{
"groupName": "Group 3",
"id": "Price",
"options": [
{
"name": "$0 - $9",
"selected": false
},
{
"name": "$9 - $19",
"selected": false
},
{
"name": "$20 - $29",
"selected": false
}
],
"range": {
"min": 5,
"max": 20
}
}
]
result3 = [
{
"groupName": "Group 2",
"id": "Brand",
"name": "brand2",
},
{
"groupName": "Group 3",
"id": "Price",
"min": 5,
"max": 20
}
]
I want to use reduce to get these above (result1, result2 & result3) solutions. Could someone help me with this?
Edited to check scenario where two are selected in the same group, solution resulting in result1.