I have a meta as below:
obj = {
meta: [['type', 'test1'], ['key2', 'value2']],
value: 'text1',
}
Want to read value test by passing the key type
expected result is test1
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Could you put your expected result here?Anh Le– Anh Le2022-02-21 07:44:41 +00:00Commented Feb 21, 2022 at 7:44
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1'type' isn't a key. It's a member of an array of strings. Maybe you want to transform your data before you use it.nlta– nlta2022-02-21 07:45:49 +00:00Commented Feb 21, 2022 at 7:45
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what happen if meta have more than two values ?jeremy-denis– jeremy-denis2022-02-21 07:48:19 +00:00Commented Feb 21, 2022 at 7:48
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@AnhLe test should be the resultBeu– Beu2022-02-21 07:48:24 +00:00Commented Feb 21, 2022 at 7:48
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@jeremy-denis yes it will have, edited my questionBeu– Beu2022-02-21 07:49:51 +00:00Commented Feb 21, 2022 at 7:49
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3 Answers
You could use Object.fromEntries()
const obj = {
meta: [['type', 'test'], ['key2', 'value2']],
value: 'text1',
}
const key = 'type'
const res = Object.fromEntries(obj.meta)[key];
console.log(res)
Comments
You should restructure meta as an object instead of an array of pairs as:
obj = {
meta: {
'type': 'test',
'key2': 'value2'
}
value: 'text1',
}
Now, you can access what you need as obj['meta']['type'] or obj.meta.type.
1 Comment
Beu
meta is an array of arrays
obj = {
meta: [['type', 'test'], ['key2', 'value2']],
value: 'text1',
}
for(let arr of obj.meta){
if(arr[0]==='type'){
return arr[1];
}
}
or
const res=obj.meta.find(arr=>arr[0]==="type");
if(res && res.length) return res[1]
Notice that this code returns only the first "type". If you have "type" twice you'll get the first result.
