How to find an element by a known src attribute using Selenium Python

To locate the element as the value of src attribute is know to you, you can use either of the following Locator Strategies:

• Using css_selector:

  element = driver.find_element(By.CSS_SELECTOR, "img.Liguzb[src*='gstatic.com/images/icons/material/system_gm/1x/place_gm_blue_24dp']")
  

• Using xpath:

  element = driver.find_element(By.XPATH, "//img[@class='Liguzb' and contains(@src, 'gstatic.com/images/icons/material/system_gm/1x/place_gm_blue_24dp')]")
  

To locate a visible element instead of presence_of_element_located() you need to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following locator strategies:

• Using CSS_SELECTOR:

  element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "img.Liguzb[src*='gstatic.com/images/icons/material/system_gm/1x/place_gm_blue_24dp']")))
  

• Using XPATH:

  element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//img[@class='Liguzb' and contains(@src, 'gstatic.com/images/icons/material/system_gm/1x/place_gm_blue_24dp')]")))
  

• Note : You have to add the following imports :

  from selenium.webdriver.support.ui import WebDriverWait
  from selenium.webdriver.common.by import By
  from selenium.webdriver.support import expected_conditions as EC