Groovy execute shell script and capture output

Question

I need to set an environment variable from a Groovy script, the value of the env var should be produced with the AWS CLI, my command

def proc ='aws codeartifact get-authorization-token --region=eu-central-1 --domain companyname --domain-owner accountnumber --query authorizationToken --output text'.execute()
env.CODEARTIFACT_AUTH_TOKEN = proc.in.text

But I get an error message

10:59:47  Caused: java.io.IOException: Cannot run program "aws": error=2, No such file or directory

I am new to Groovy and looking around for solutions, any tips in the meanwhile?

What is your operating system? AWS CLI version?

Vy Do
– Vy Do

2022-03-02 14:47:11 +00:00
Commented Mar 2, 2022 at 14:47 — Vy Do
– Vy Do, Commented Mar 2, 2022 at 14:47

Vy Do · Accepted Answer · 2022-03-02 14:46:54Z

0

Your path variable maybe wrong. Check it by

println System.getenv('PATH')

then fix it.

answered Mar 2, 2022 at 14:46

Vy Do

1

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1 Comment

JBoy Over a year ago

its already in the path, if i ssh to the host and try running aws commands it works

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