Bytes Concatenation problem with None in Python

Question

total = None

for i in range(2):

        item_1 = b'\x01'

        item_2 = b'\x02'

        item_3 = b'\x03'
       
        # concatenation
        combined = item_1 + item_2 + item_3 # which makes b'\x01\x02\03'
        
        total = total + combined            # to make b'\x01\x02\03\x01\x02\03'

In the above, I get a error because I cannot concatenate None with Bytes. One way I am thinking is to give some value(let's say b'\x00') to total and remove in the total later, but not sure how to do it. Can someone please tell a away to achieve the above

use total= b'' instead of None

Tomáš Šturm
– Tomáš Šturm

2022-03-08 10:23:33 +00:00
Commented Mar 8, 2022 at 10:23 — Tomáš Šturm
– Tomáš Šturm, Commented Mar 8, 2022 at 10:23
@TomášŠturm , I will try that. Thankyou

pjrockzzz
– pjrockzzz

2022-03-08 11:04:00 +00:00
Commented Mar 8, 2022 at 11:04 — pjrockzzz
– pjrockzzz, Commented Mar 8, 2022 at 11:04

voidpointercast · Accepted Answer · 2022-03-08 19:57:20Z

1

Filter on possible None arguments. filter(None, args) will return an iteratable that holds all values with bool(value) == True

def combine_bytes(*args):
return b''.join(filter(None, args))

You can then call:

combine_bytes(b'\x01', None, b'\x02', b'\x03', False)

answered Mar 8, 2022 at 19:57

voidpointercast

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