Adding labels to grouped violin plot matplotlib [duplicate]

Question

I have a plot of 3 groups of 3 violins (so 9 violin plots) on the same axis and I want to label the groups, here is my attempt:

ax = plt.violinplot([method1[:,0].flatten(),method2[:,0].flatten(),method3[:,0].flatten()],positions= [1,2,3],showmeans=True,showmedians=False)
ax = plt.violinplot([method1[:,1].flatten(),method2[:,1].flatten(),method3[:,1].flatten()],positions=[5,6,7],showmeans=True,showmedians=False)
ax = plt.violinplot([method1[:,2].flatten(),method2[:,2].flatten(),method3[:,2].flatten()],positions=[9,10,11],showmeans=True,showmedians=False)


#positions = (([1,2,3],[5,6,7],[9,10,11]))
#labels = ( "method 1", "method 2","method 3")
#plt.xticks(positions = [2,6,10], labels)

ax.set_xticklabels(['method 1','method 2','method 3'])
ax.set_xticks([2,6,10])

I get the violin plots as intended but I can't figure out how to add the labels correctly. I get the error:

module 'matplotlib.pyplot' has no attribute 'set_xticklabels'

Try this: ax.xticks([2, 6, 10], labels=['method 1','method 2','method 3']) — r-beginners
– r-beginners, Commented Mar 8, 2022 at 12:43
Hi, what was the error with plt.xticks([2,6,10], ['method 1','method 2','method 3'])? I thought that should work. — Duca
– Duca, Commented Mar 8, 2022 at 12:45
@duca It said positional argument follows keyword argument with square or round brackets and points to the comma before labels — Lizardinablizzard
– Lizardinablizzard, Commented Mar 8, 2022 at 12:55
@r-beginners I get 'dict' object has no attribute 'xticks' — Lizardinablizzard
– Lizardinablizzard, Commented Mar 8, 2022 at 12:56
Oh, now it works with that when I change the numbers - thanks! — Lizardinablizzard
– Lizardinablizzard, Commented Mar 8, 2022 at 13:08

Lizardinablizzard · Accepted Answer · 2022-03-08 13:11:56Z

1

positions = (2, 6, 10)
labels = ( "m1", "m2","m3")
plt.xticks(positions, labels)

answered Mar 8, 2022 at 13:11

Lizardinablizzard

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