I know this has been asked many times and I did find a solution, value.replace(/^([\d,]+)$|^([\d,]+)\.0*$|^([\d,]+\.[0-9]*?)0*$/, "$1$2$3").
But... I'm no regex expert so I'm just curious as to why this doesn't work /[\.0]+$/... 10 should return 10 but I just can't figure out how to exclude whole numbers that end with 0s.
1.7500, 1.1010, 1.0000, 10
1.75, 1.101, 1, 1
You might shorten the pattern to match either a dot with only zeroes, or use a non greedy match for the digits with a capture group and match optional trailing zeroes.
If you want to match digits and comma's the first \d+ can also be [\d,]+ as you already have in your pattern.
If there should be at least a single digit after the dot, then the quantifier can be a plus .\d+?
^(\d+)(?:\.0+|(\.\d*?)0+)$
See a regex 101 demo.
[
"1.7500",
"1.1010",
"1.0000",
"10"
].forEach(s =>
console.log(s.replace(/^(\d+)(?:\.0+|(\.\d*?)0+)$/, "$1$2"))
);
/[\.0]+$/does not require the input to have a decimal point. You need to require it.?that the decimal was required?[\.0]leaves the choice to match with either.or with0. So if every time (of the repeated+) it is an0, it will still match -- without ever having matched a dot.(?<=\.)but can't do anything with the group, like test if it ends with 0s. Am I on the right track?