Can't realloc character string in C

Question

I'm having some issues with realloc, for example, this code

    char *s = (char*)malloc(sizeof(char)*17);
    s = "bruhbruhlmaolmao";
    s = (char*)realloc(s, sizeof(char)*18);
    if(s == NULL) printf("Memory allocation failed");
    else printf("%s\n",s);

I'm trying to reallocate the memory chunk that s is pointing at to a larger memory location in the heap.

I've compiled it and the compiler returns no warning. When I run the executable, It prints out nothing. I hope you can explain to me why and how to fix it

s = "bruhbruhlmaolmao"; "throws away" the memory you just allocated and instead points the pointer at a string literal. And you cannot realloc a string literal — UnholySheep
– UnholySheep, Commented Mar 12, 2022 at 17:47
C doesn't let you copy an array with a single assignment statement. You can use a loop or one of the functions in string.h. — stark
– stark, Commented Mar 12, 2022 at 17:55
s = "bruhbruhlmaolmao"; should be strcpy(s, "bruhbruhlmaolmao"); — Iłya Bursov
– Iłya Bursov, Commented Mar 12, 2022 at 17:57

Hibiki Supersanta · Accepted Answer · 2022-03-12 18:18:58Z

1

Well, apparently I made a dumb decision by assigning s to a string: s = "bruhbruhlmaolmao";, what I should really do is use something in string.h library like strcpy

answered Mar 12, 2022 at 18:18

Hibiki Supersanta

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