python: find value in multiple variables

Question

this is my situation:

I have variables of x coordinates. .

x_1 = 24
x_2 = 94
x_3 = 120

And I have weather stations that are located on one of these x values.

station_1 = 100
station_2 = 80
station_3 = 94
station_4 = 24
station_6 = 120
station_7 = 3

The station x coordinates stay the same but not the x_1, x_2 and x_3 coordinates. They change depending on the input of my script. Although the x_ coordinates always matches one of the station coordinates.

Now I need to find the matching station with the x_ coordinate. I tried this:

if x_1 == 100:
    x1_station = station_1
elif x_1 == 80:
    x1_station = station_1
elif x_1 == 94:
    x1_station = station_1    
elif x_1 == 24:
    x1_station = station_1
elif x_1 == 120:
    x1_station = station_1
elif x_1 == 3:
    x1_station = station_1
else:
    print("no matching stations")
    
print(x1_station)

But this will not work. And it also looks a bit of to much repetition. Does anyone know how to solve this? Maybe a for loop would help.

Kind regards,

Simon

@simonDL can you verify if your provided code is correct? Looks like those section_1 variables need to be changed in if conditions — Hammad
– Hammad, Commented Mar 18, 2022 at 8:35
@Hammad, yes you are right. I made this as an example code and got a bit confused, sorry. But now I edited it right. But if I have to use this code on like 10 x coordinates the code gets very long. I think there should be a better way to do this. — SimonDL
– SimonDL, Commented Mar 18, 2022 at 8:44
looks like you should really use a container, having numbered variables should be replaced by a list or dictionary — mozway
– mozway, Commented Mar 18, 2022 at 8:50

mashuptwice · Accepted Answer · 2022-03-18 13:32:57Z

2

Maybe I confuse something here, but from my understanding you could use a dictionary here:

dict_st={80:station_4,90:station_3,70:station_2}
x_1_station = dict_st.get(x_1,'no matching stations')

edited Mar 18, 2022 at 13:32

mashuptwice

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answered Mar 18, 2022 at 8:38

smart lph

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RivenSkaye · Accepted Answer · 2022-03-18 08:40:20Z

2

Have you considered using a dict here? You could use the station coordinates for the keys to ensure uniqueness and then have whatever information you need to store from them as the values.

stations = {
    100: station_1_data,
    80: station_2_data,
    ...
}

x1_station = stations.get(x_1)
if x1_station is None:
    print("No matching stations")

answered Mar 18, 2022 at 8:40

RivenSkaye

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Comments

Pony Ma · Accepted Answer · 2022-03-18 08:43:52Z

0

station_map = {
    80: station_1,
    100: station_2,
    120: station_3,

}
station = mapp.get(x)

It might be easier to write it this way, but I don't konw if it will solve your problem

answered Mar 18, 2022 at 8:43

Pony Ma

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