Iterate through nested array of object in an Array of objects

Question

Trying to make a select filter with all the unique coins, but not getting to the end of it correctly.

When looping through data I can get a list of all the coins like this.

const uniqueCoins = data.map((item) => {
  item.currencies.map((subItem) => 
  console.log(subItem))
});

I also want to use the Set method and spread operator to get just unique values but I'm not sure how to combine all these.

const data = [
  {
    id: "1",
    name: "Digitec",
    description: "Wir akzeptieren folgende Kryptowährungen",
    currencies: [
      {coin: "Bitcoin"},
      {coin: "Ethereum"},
      {coin: "XRP"},
    ],
    link: "webseite besuchen",
  },
  {
    id: "2",
    name: "Galaxus",
    description: "Wir akzeptieren folgende Kryptowährungen",
    currencies: [
      {coin: "Bitcoin"},
      {coin: "Monero"},
      {coin: "XRP"},
    ],
    link: "webseite besuchen",
  },
  {
    id: "3",
    name: "Brack.ch",
    description: "Wir akzeptieren folgende Kryptowährungen",
    currencies: [
      {coin: "Litecoin"},
      {coin: "Dogecoin"},
      {coin: "XRP"},
    ],
    link: "Onlineshop besuchen",
  },
];

Do you just want an array of the unique coin names like this: ['Bitcoin', 'Monero', 'Dogecoin', ...]? — mhodges
– mhodges, Commented Mar 22, 2022 at 16:54
Does this answer your question? Get unique values from array of arrays — tevemadar
– tevemadar, Commented Mar 22, 2022 at 17:14

mayank kaul · Accepted Answer · 2022-03-22 20:51:45Z

2

You can reduce the array and then remove the duplicates:

const uniqueCoins = [...new Set(data.reduce((prev, cur) => prev.concat(cur.currencies.map(cur => cur.coin)), []))]

To break it down :

Step 1 : Get all the coins in an array using array.reduce

const coins = data.reduce((prev, cur) => prev.concat(cur.currencies.map(cur => cur.coin)), []);

Step 2 : Remove all the uniques in the array

const uniqueCoins = [...new Set(coins)];

edited Mar 22, 2022 at 20:51

answered Mar 22, 2022 at 20:33

mayank kaul

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Comments

Andy · Accepted Answer · 2022-03-22 17:31:07Z

Start by combining all the coin values from all the currencies arrays using map, and flatMap, add that flattened array to a Set to dedupe the elements, and then spread the Set back out into an array.

const data=[{id:"1",name:"Digitec",description:"Wir akzeptieren folgende Kryptowährungen",currencies:[{coin:"Bitcoin"},{coin:"Ethereum"},{coin:"XRP"}],link:"webseite besuchen"},{id:"2",name:"Galaxus",description:"Wir akzeptieren folgende Kryptowährungen",currencies:[{coin:"Bitcoin"},{coin:"Monero"},{coin:"XRP"}],link:"webseite besuchen"},{id:"3",name:"Brack.ch",description:"Wir akzeptieren folgende Kryptowährungen",currencies:[{coin:"Litecoin"},{coin:"Dogecoin"},{coin:"XRP"}],link:"Onlineshop besuchen"}];

// Get a new array of coins for each object, and then
// flatten all of them into one array
const coins = data.flatMap(obj => {
  return obj.currencies.map(currency => currency.coin);
});

// Create a set from the coins array
const set = new Set(coins);

// `sort and `map` over the array to produce
// an array of HTML for each option
const options = [...set].sort().map(option => {
  return `<option value=${option}>${option}</option>`;
});

// Add those options to a select
const select = `
  <select>
    <option disabled selected>Choose a coin</option>
    <option disabled>----</option>
    ${options.join('')}
  </select>
`

// Add that HTML to a container
document.body.insertAdjacentHTML('beforeend', select);

Additional documentation

thats exactly what i was looking for. How do you combine this into a select dropdown menu?

PeterKA · Accepted Answer · 2022-03-22 17:59:37Z

1

Use .flatMap() method to get the coins sub-arrays and to flatten then array, then use new Set() to get unique values.

const data = [{id: "1",name: "Digitec",description: "Wir akzeptieren folgende Kryptowährungen",currencies: [{coin: "Bitcoin"},{coin: "Ethereum"},{coin: "XRP"}],link: "webseite besuchen"},{id: "2",name: "Galaxus",description: "Wir akzeptieren folgende Kryptowährungen",currencies: [{coin: "Bitcoin"},{coin: "Monero"},{coin: "XRP"}],link: "webseite besuchen"},{id: "3",name: "Brack.ch",description: "Wir akzeptieren folgende Kryptowährungen",currencies: [{coin: "Litecoin"},{coin: "Dogecoin"},{coin: "XRP"}],link: "Onlineshop besuchen"}];

const coins = [ ...new Set(
    data.flatMap(({currencies}) => currencies.map(({coin}) => coin))) 
];

console.log( coins );

edited Mar 22, 2022 at 17:59

answered Mar 22, 2022 at 17:29

PeterKA

24.7k5 gold badges28 silver badges52 bronze badges

Comments

peinearydevelopment · Accepted Answer · 2022-03-22 17:03:30Z

const data = [
  {
    id: "1",
    name: "Digitec",
    description: "Wir akzeptieren folgende Kryptowährungen",
    currencies: [
      {coin: "Bitcoin"},
      {coin: "Ethereum"},
      {coin: "XRP"},
    ],
    link: "webseite besuchen",
  },
  {
    id: "2",
    name: "Galaxus",
    description: "Wir akzeptieren folgende Kryptowährungen",
    currencies: [
      {coin: "Bitcoin"},
      {coin: "Monero"},
      {coin: "XRP"},
    ],
    link: "webseite besuchen",
  },
  {
    id: "3",
    name: "Brack.ch",
    description: "Wir akzeptieren folgende Kryptowährungen",
    currencies: [
      {coin: "Litecoin"},
      {coin: "Dogecoin"},
      {coin: "XRP"},
    ],
    link: "Onlineshop besuchen",
  },
];

const uniqueCoins = [... new Set(data.map(item => item.currencies.map(subItem => subItem.coin))
                        .reduce((arr1, arr2) => arr1.concat(arr2), []))];
console.log(uniqueCoins);

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