How to fill a copy of an array with zeros without using array functions?

Question

My sample Mid-term asks me to write a method that takes an array called origArr and returns a copy of it. The returned copy should have a specified length called len and if len is greater than origArr's length than the extra slots are filled with zero. The question also states that no functions of the array class can be used. When I print the new array it doesn't add the zero's to the extra slots. So far my code is:

public static void main(String[] args) {
    
    int[] origArr = {1,2,3,4,5,6};
    int len = 0;
    int[] array = myCopyOf(origArr, len);
    
    for (int i=0; i < array.length; i++) {
        System.out.println(array[i]);
    }
    
}
    

public static int[] myCopyOf(int[] origArr, int len) {
    
        //declare new array//
        int[] myCopyOf = new int[origArr.length];
        
        //declare length should be equal to origArr' length//
        len = origArr.length;
        
        if (len > origArr.length) {
            for (int i = 0; i < origArr.length; i++) {
                myCopyOf[i] = origArr[i] + 0;
                
                                                        }
        
            
                                        }
        return myCopyOf;
}

len = origArr.length; if (len > origArr.length) { Think about those two lines. — C. Weber
– C. Weber, Commented Mar 22, 2022 at 20:58
re //declare length should be equal to origArr' length// This is in direct contradiction to the requirements as stated by you: * — passer-by
– passer-by, Commented Mar 22, 2022 at 22:37

Bohemian · Accepted Answer · 2022-03-22 22:39:40Z

2

In Java, primitives - int is a primitive - always have a value; if they aren't initialized explicitly with a value they are assigned their default value, which for numeric primitives is zero.

This means that when you create a int[], all elements are 0, so you don't have to do anything special - the extra elements are already 0.

There are 2 bugs in your code.

First bug:

int[] myCopyOf = new int[origArr.length];

Should be:

int[] myCopyOf = new int[len];

Second bug: you should delete the if and correct the loop termination condition:

for (int i = 0; i < origArr.length && i < len; i++) {
    myCopyOf[i] = origArr[i];
}

which handles when len is less or greater than the array's length.

Also, no need for the + 0.

edited Mar 22, 2022 at 22:39

answered Mar 22, 2022 at 21:03

Bohemian♦

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1 Comment

Bohemian Over a year ago

@user16320675 true, but I was deliberately keeping it simple.

Code-Apprentice · Accepted Answer · 2022-03-22 21:08:01Z

0

        int[] myCopyOf = new int[origArr.length];

Here you create a new array with the same length as the original array. But your requirements say that the length must be what is specified by the len parameter, so use that:

        int[] myCopyOf = new int[len];

This will automatically fill in zeros when len is greater than origArray.length. You will need to be careful when origArray is shorter, though. You can make a small modification to the for loop to fix that. I will leave the details as an exercise.

answered Mar 22, 2022 at 21:08

Code-Apprentice

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