python string format for variable tuple lengths

Question

I have a tuple of numbers let's say nums = (1, 2, 3). The length of nums is not constant. Is there a way of using string formatting in python to do something like this

>>>print '%3d' % nums

that will produce

>>>   1   2   3

Hope it's not a repeat question, but I can't find it if it is. Thanks

Gerrat · Accepted Answer · 2011-08-23 15:28:10Z

7

Try this:

print ('%3d'*len(nums)) % tuple(nums)

answered Aug 23, 2011 at 15:28

Gerrat

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Comments

nmichaels · Accepted Answer · 2011-08-23 15:39:55Z

4

Since nobody's said it yet:

''.join('%3d' % num for num in nums)

answered Aug 23, 2011 at 15:39

nmichaels

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Comments

Chris Pickett · Accepted Answer · 2011-08-23 15:28:20Z

3

You could use .join():

nums = (1, 2, 3)
"\t".join(str(x) for x in nums) # Joins each num together with a tab.

answered Aug 23, 2011 at 15:28

Chris Pickett

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PapaKuma · Accepted Answer · 2016-07-01 05:43:09Z

2

Using ''.format

nums = (1, 2, 3)
print(''.join('{:3d} '.format(x) for x in nums))

producing

>>>  1  2  3

answered Jul 1, 2016 at 5:43

PapaKuma

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viraptor · Accepted Answer · 2011-08-23 16:46:35Z

1

Is this enough for you?

print ' '.join(str(x) for x in nums)

edited Aug 23, 2011 at 16:46

answered Aug 23, 2011 at 15:28

viraptor

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Comments

Maehler · Accepted Answer · 2012-06-08 14:23:44Z

-1

params = '%d'
for i in range(1,15):
    try:
        newnum = (params)%nums
    except:
        params = params + ',%d'
        next
    print newnum

edited Jun 8, 2012 at 14:23

Maehler

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answered Jun 6, 2012 at 20:39

RightmireM

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2 Comments

Maehler Over a year ago

Have you even tried to run this? Hint: it will crash if the size of nums is larger than 1.

Maehler Over a year ago

When looking at it now, I see how you're thinking. However, there must be an indentation error on the last line. The way the code is written here, it will crash if len(nums) > 1, and if len(nums) == 1, it will print the number 14 times.

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