So I have a string (string = "Cipher Programming - 101!"), I want to split it by six chars (spaces and special symbols included) and store result as list in Python.
expected output: ['Cipher', ' Progr', 'amming', ' - 101', '!']
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1What have you tried so far? Also, you probably don't want to call a Python variable 'string'jackal– jackal2022-03-27 11:30:03 +00:00Commented Mar 27, 2022 at 11:30
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Tried to solve it with for loop n = 6 string = "Cipher Programming - 101!" str_size = len(string) part_size = n k = 0 for i in string: if k % part_size == 0: print() print(i, end="") k += 1 but I am trying to write the code inside function returning only list (without using print)saba morchilashvili– saba morchilashvili2022-03-27 11:39:27 +00:00Commented Mar 27, 2022 at 11:39
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2 Answers
Just a normal for loop will do the trick:
string = "Cipher Programming - 101!"
n = 6
[line[i:i+n] for i in range(0, len(string), n)]
4 Comments
Bialomazur
It's actually a list comprehension, not a normal for loop.
António Rebelo
@Bialomazur Yes, my bad
saba morchilashvili
@AntónioRebelo what does the third line do? when I run it says line needs declaration. If you shortened your code, could you please upload the full version of it?
António Rebelo
Check @Bialomazur 's solution for a more straightforward solution that is easier to understand. If you have not come across list-comprehensions I suggest you do so, this is what I used in that solution and if you haven't heard of them it can be quite tricky to understand how it works. I am not sure what "needs declaration" means but I think the code should work.
The answer above works very well - is very compact and elegant, but for sake of understanding it a bit better, I've decided to include an answer with a regular for-loop.
string = "Cipher Programming - 101!" # can be any string (almost)
result = []
buff = ""
split_by = 6 # word length for each string inside of 'result'
for index, letter in enumerate(string):
buff += letter
# first append and then reset the buffer
if (index + 1) % split_by == 0:
result.append(buff)
buff = ""
# append the buffer containing the remaining letters
elif len(string) - (index + 1) == 0:
result.append(buff)
print(result) # output: ['Cipher', ' Progr', 'amming', ' - 101', '!']
2 Comments
jackal
Please see António Rebelo's answer for an elegant solution
Bialomazur
@ArthurKing I have, please read my statement before the actual code. It was my intention to make the code longer with more 'baby-steps' involved. I think it plays together quite well with António Rebelo's much shorter solution with a list-comprehension.