0

How to find name using id. means iterate object. create a function const searchName =()=>{} suppose if pass 3 in function so I'd want to show .... what the name of user like this

const data = [{
    "service": [
        "BUSINESS",
        "LEGAL",
        "FINANCE",
        "ADVERTISEMENT"
    ],
    "service1": [
        { "id": 1, "name": "a" },
        { "id": 2, "name": "b" },
        { "id": 3, "name": "c" },
        { "id": 4, "name": "d" },
    ],
    "service2": [
        { "id": 5, "name": "e" },
        { "id": 6, "name": "f" },
        { "id": 7, "name": "g" },
        { "id": 8, "name": "h" },
    ],
    "service3": [
        { "id": 9, "name": "i" },
        { "id": 10, "name": "j" },
        { "id": 11, "name": "k" },
        { "id": 12, "name": "l" },
    ],
    "service4": [
        { "id": 13, "name": "m" },
        { "id": 14, "name": "n" },
        { "id": 15, "name": "o" },
        { "id": 16, "name": "p" },
    ],
}
]

suppose user pass 3 so I want to return { "id": 3, "name": "c" } like this. I'm trying to iterate this and find the name of the user by id but I didn't understand this iteration so I need your help.

3 Answers 3

1

check this code.... Enter any id number

const data = [{
                    "service": [
                        "BUSINESS",
                        "LEGAL",
                        "FINANCE",
                        "ADVERTISEMENT"
                    ],
                    "service1": [
                        { "id": 1, "name": "a" },
                        { "id": 2, "name": "b" },
                        { "id": 3, "name": "c" },
                        { "id": 4, "name": "d" },
                    ],
                    "service2": [
                        { "id": 5, "name": "e" },
                        { "id": 6, "name": "f" },
                        { "id": 7, "name": "g" },
                        { "id": 8, "name": "h" },
                    ],
                    "service3": [
                        { "id": 9, "name": "i" },
                        { "id": 10, "name": "j" },
                        { "id": 11, "name": "k" },
                        { "id": 12, "name": "l" },
                    ],
                    "service4": [
                        { "id": 13, "name": "m" },
                        { "id": 14, "name": "n" },
                        { "id": 15, "name": "o" },
                        { "id": 16, "name": "p" },
                    ],
                }]
            var itemobj = ''
            const searchName =(val)=>{
                    console.log('searchname')
                    data.map((item)=>{
                        let obj = Object.keys(item)            
                        obj.map((data)=>{
                            let inrdata = item[data]
                            inrdata.map((initem)=>{                    
                                 let lastdata = initem.id===val?itemobj=initem:null  
                                  
                                
                            })

                        })
                    })
                }
                
            searchName(3)
             console.log(itemobj)

Sign up to request clarification or add additional context in comments.

1 Comment

Quite complex... could you add explanations to your answer?
1
function searchName(id) {
let result = null;
  for (const [key, value] of Object.entries(data)) {
    if (key === "service") continue
    result = value.filter(obj => {
        return obj.id === id
        })
    if (result) break
  }
  return result ? result[0] : null
}

I iterate through keys, I just skip "service" one since it's not revelant. Then, I filter the "serviceN" array, it will return an array of object (only one if found, empty array if not found).

If it's found, we stop iterating.

Then we return either the first (and logically only element) or null if not found

Comments

1

You could use a combination of flat and find to get get the user by id

function searchName(id) {
  return data
    .flatMap((item) => Object.values(item))
    .flat()
    .find((user) => user.id === id);
}

const result = searchName(3); // { id: 3, name: 'c' } | undefined

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.