Why value null after converting in int in kotlin

Question

Hey I am working in android kotlin. I am getting double value in the form of string from server. I am converting that value in Int and checking that value is not null using toIntOrNull(). But I am getting 0 all the time.

Value coming from server

"value": "79.00"

My Data class

import android.os.Parcelable
import kotlinx.android.parcel.Parcelize

@Parcelize
data class Detail(
    val value: String? = null,
) : Parcelable {
    val valueInDouble by lazy {
        value?.toDoubleOrNull() ?: Double.NaN
    }
    val valueInInt by lazy {
        value?.toIntOrNull() ?: 0
    }
}

whenever I print the value of valueInInt in console it returns 0. I know that 0 is coming because of toIntOrNull() but my value is coming from server which is not null. But I don't understand why this is happening. Can someone guide me please?

Expected Output

79

Actual Output

0

I know that default value is 0. But my value coming from server is 79.00 — Vivek Modi
– Vivek Modi, Commented Mar 28, 2022 at 17:19

Tenfour04 · Accepted Answer · 2022-03-28 17:23:01Z

4

If the String value has a decimal in it, it cannot be parsed as an integer, so toIntOrNull() will return null.

You should parse as a Double and then convert the Double to an Int based on whatever type of rounding is appropriate for your use case.

val valueInInt by lazy {
    value?.toDoubleOrNull()?.roundToInt() ?: 0
}

answered Mar 28, 2022 at 17:23

Tenfour04

95.1k14 gold badges125 silver badges181 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Why value null after converting in int in kotlin

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related